The following observations are lifetimes (days) subsequent to diagnosis for individuals suffering from blood cancer. 115 462 517 1064 1166 739 743 789 807 1192 1222 1222 1252 181 256 418 441 866 925 983 1026 1063 1277 1290 1358 1409 1456 1479 1519 1578 1578 1599 1815 1852 1899 1925 1965 1369 1604 1605 1696 1735 1799 (a) Can a confidence interval for true average lifetime be calculated without assuming anything about the nature of the lifetime distribution? Explain your reasoning. [Note: A normal probability plot of the data exhibits a reasonably linear pattern.] O Yes, the range is sufficiently large enough for the confidence interval to be reasonable. O No, the sample size is not large enough for the confidence interval to be reasonable. O No, we need to assume that the population is normally distributed. O Yes, the sample size is large enough for the confidence interval to be reasonable. O No, the range is not large enough for the confidence interval to be reasonable. (b) Calculate and interpret a confidence interval with a 99% confidence level for true average lifetime. [Hint: x = 1192.0 and s= 506.5.] (Round your answers to one decimal place.) Interpret the resulting interval. O We are 99% confident that this interval contains the true population mean. O We are 99% confident that the true population mean lies above this interval. O We are 99% confident that this interval does not contain the true population mean. O We are 99% confident that the true population mean lies below this interval.

Q: 2(3y-5)=34

A: We will see the ans in next step

Q: V-539 7. V11

A: To Determine:  Simplify

Q: Find A. A = (3A)-1 [ -3-2 4 2

A: Let us consider that                     A=abcdWe have                   (3A)-1=-3-242 ⟹…

Q: Use the graph to solve the equation: x + 5 = 0.5(x + 3)² - 2 Answer

A:

Q: 4y-12=0

A: 4y = 12 y = 3

Q: Find A. A= (4A)-¹ = 3 2 22

A:

Q: (-2) · (15 + 9) + (5 – 9 + 8)

A: Given: -2·15+9÷5-9+8

Q: 1 L (s- 4)6 J

A:

Q: 2. K 5x+5 16 35

A:

Q: What is the value for s3?

A:

Q: 14 +2

A: Adding Fractions Step 1: Make sure the bottom numbers (the denominators) are the same. Step 2: Add…

Q: -12+(4• 3) (-) I 2-14 - 3)ENTER

A:

Q: cx3 Y So So exdydx

A: .

Q: 3b-12 = 30

A:

Q: 4b2 + 8b +7 = 4

A: Given that

Q: 5×-6=37

A: Given,           5×-6=37

Q: 3n+20=15

A: solve the given 3n+20=15

Q: x+9= 12 %3D

A: Given: x+9=12

Q: 3=6

A: Suppose the empty box has value x than do the calculation.

Q: (-12)+7

A: To simplify any expression involving numbers we need to use the BODMAS rule which specifies the…

Q: Ys+1 s7105 +?4

A:

Q: Vs-+ 12²

A: To determine:

Q: 2(a+3)= -12

A: Solution: Here 2(a+3) =-12

Q: (2+34)²

A:

Q: S dr 3r+5 r3-8

A:

Q: 10 = 2(p + -4)

A: Given  10 = 2(p + -4) p =?

Q: 7k = 91

A: We will find the value of k in the following step.

Q: A binomial probability experiment is conducted with the given parameters. Use technology to find the…

A:

Q: 5xn=25

A: 5×n = 25 To find value of n

Q: Find

A: We know that,                         ∫1xdx=lnx+ c We need to find  ∫4xdx

Q: SVe -z) + 4 dz

A:

Q: 4h aー-5

A: We have to find out

Q: -3(4x-5)-6=18

A: Given: −34x−5−6=18 To determine: The value of x.