The following observations are lifetimes (days) subsequent to diagnosis for individuals suffering from blood cancer. 116 182 255 418 441 462 517 739 744 789 807 865 924 984 1025 1062 1064 1165 1191 1222 1222 1252 1278 1290 1357 1369 1409 1455 1479 1519 1578 1578 1599 1604 1605 1697 1735 1799 1815 1853 1899 1925 1966 (a) Can a confidence interval for true average lifetime be calculated without assuming anything about the nature of the lifetime distribution? Explain your reasoning. [Note: A normal probability plot of the data exhibits a reasonably linear pattern.] O No, the sample size is not large enough for the confidence interval to be reasonable. No, the range is not large enough for the confidence interval to be reasonable. O Yes, the range is sufficiently large enough for the confidence interval to be reasonable. • Yes, the sample size is large enough for the confidence interval to be reasonable. O No, we need to assume that the population is normally distributed.

The following observations are lifetimes (days) subsequent to diagnosis for individuals suffering from blood cancer. 116 182 255 418 441 462 517 739 744 789 807 865 924 984 1025 1062 1064 1165 1191 1222 1222 1252 1278 1290 1357 1369 1409 1455 1479 1519 1578 1578 1599 1604 1605 1697 1735 1799 1815 1853 1899 1925 1966 (a) Can a confidence interval for true average lifetime be calculated without assuming anything about the nature of the lifetime distribution? Explain your reasoning. [Note: A normal probability plot of the data exhibits a reasonably linear pattern.] O No, the sample size is not large enough for the confidence interval to be reasonable. No, the range is not large enough for the confidence interval to be reasonable. O Yes, the range is sufficiently large enough for the confidence interval to be reasonable. • Yes, the sample size is large enough for the confidence interval to be reasonable. O No, we need to assume that the population is normally distributed.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one particular customer for the past 20 months. Use the given data to answer parts (a) and (b). (a) Determine the standard deviation and interquartile range of the data. S= (Round to two decimal places as needed.) 324 515 402 458 338 464 343 384 548 514 495 444 365 423 501 552 328 496 394 429
Are the snow conditions a factor in the number of visitors at a ski resort? The table below shows data that was collected. Machine Made Powder Hard Packed 1224 1733 1427 1976 1501 1542 1432 2493 1022 1080 1707 1350 1383 2410 2474 1033 2137 2051 1892 1710 2029 1022 1006 Assume that all distributions are normal, the three population standard deviations are all the same, and the data was collected independently and randomly. Use a level of significance of α=0.01α=0.01.H0: μ1=μ2=μ3H0: μ1=μ2=μ3H1:H1: At least two of the means differ from each other. The test-statistic for this data: F = The p-value for this sample =
The following observations are lifetimes (days) subsequent to diagnosis for individuals suffering from blood cancer. 116 181 461 517 739 743 789 865 255 984 1357 419 441 1026 1063 1166 1369 1408 1455 1479 1063 924 1290 1191 1222 1222 1277 1519 1578 1578 1899 1926 1966 1603 1605 1696 1735 1799 1815 1852 807 1252 1599 (a) Can a confidence interval for true average lifetime be calculated without assuming anything about the nature of the lifetime distribution? Explain your reasoning. [Note: A normal probability plot of the data exhibits a reasonably linear pattern.] Yes, the range is sufficiently large enough for the confidence interval to be reasonable. No, we need to assume that the population is normally distributed. No, the sample size is not large enough for the confidence interval to be reasonable. Yes, the sample size is large enough for the confidence interval to be reasonable. No, the range is not large enough for the confidence interval to be reasonable. (b) Calculate and…
Are the snow conditions a factor in the number of visitors at a ski resort? The table below shows data that was collected. Hard Packed Machine Made Powder 2457 1401 1708 1484 1895 2193 2334 1849 2803 1816 1870 1842 1792 1873 2969 2219 989 1791 1504 1917 2143 1265 1881 1545 2341 1531 Assume that all distributions are normal, the three population standard deviations are all the same, and the data was collected independently and randomly. Use a level of significance of a = 0.05. Ho: µi = µ2 = µ3 H1: At least two of the means differ from each other. 1. For this study, we should use Select an answer v 2. The test-statistic for this data = (Please show your answer to 3 decimal places.) 3. The p-value for this sample = (Please show your answer to 4 decimal places.) 4. The p-value is Select an answer 5. Base on this, we should Select an answer v hypothesis 6. As such, the final conclusion is that... O There is insufficient evidence to support the claim that snow conditions is a factor in the…
Listed below, from left to right and then top to bottom, are numbers of law enforcement fatalities for recent and consecutive years. First find the median, identify each value as being above the median or below the median, then test for randomness above and below the median using the runs test with a significance level of α=0.05. Is there a trend? 211 177 147 164 175 143 164 181 149 161 188 161 174 233 163 152 169 176 159 194 The median is enter your response here. (Type an integer or a decimal. Do not round.) Determine the null and alternative hypotheses. Determine the test statistic. enter your response here (Type an integer or decimal rounded to two decimal places as needed.)
As the plant operations manager for Oxford Biotech, you are responsible for monitoring the amount of product placed in each carton. To be consistent with package labeling, cartons should contain a mean of 368 grams of product. Thousands of cartons are produced during a shift, and weighing every single carton was determined to be too time-consuming, costly, and inefficient. Instead, a random sample of cartons is selected. Based on your analysis of the sample, you had to decide whether to maintain, alter, or shut down the process. Using the concept of the sampling distribution of the mean, you can determine the probability that such a sample mean could have been randomly selected from a population with mean of 368 grams. Specifically, if a sample size of n = 25 is selected from a population with mean of 368 grams and standard deviation of 15, the probability of selecting a sample with a mean of 365 grams or less is Enter your answers using 4 decimal places (Do NOT enter as a percentage).
39 b. Construct a 95% confidence interval of the mean pulse rate for adult males Males Females 85 81 73 93 51 59 59 65 50 54 63 83 51 77 74 84 52 88 60 54 72 36 62 68 61 81 80 78 82 78 64 62 67 67 95 77 43 61 87 65 74 86 61 79 73 71 71 73 53 85 66 90 55 87 80 90 71 89 65 95 66 70 95 89 57 81 65 79 59 75 57 55 70 102 72 76 87 79 61 79
Figure 1 shows the no. of Australian tourist arrivals to Malaysia from the year 2010 to 2019. 2010 2011 2012 2013 2014 2015 2016 2017 2018 2019 0.58 0.56 0.51 0.53 0.57 0.49 0.38 0.35 0.35 0.37 Figure 1: Average no. of Australian tourist arrivals to Malaysia per year Based on the data in Figure 1, construct a 95% confidence interval to estimate the mean no. of Australian tourist arrivals per year to Malaysia. 2. Based on the data in Figure 1, at 0.05 level of significance, can we claim that in general, the mean no. of Australian tourist arrivals per year to Malaysia is lower than 4 million. Use the critical value approach. 3. Compare the result in 1(a) and 1(b) and make your final conclusion.
The data represent a sample of the number of home fires started by candles for the past several years. (Data are from the National Fire Protection Association.) Find the 99% confidence interval for the mean number of home fires started by candles each year. Round your answer to one decimal place. (You are allowed to use a class calculator or graphing calculator to find the mean and standard deviation.) 5460 5900 6090 6310 7160 8440