The following MINITAB output presents the results of a hypothesis test for the differenceP1- P2 between two population proportions.Test and CI for Two ProportionsSampleх NSample p41 970.422680237 610.606557Difference = p (1) – p (2)Estimate for difference: -0.18387795% CI for difference: (-0.341016, -0.026738)Test for difference = 0 (vs not = 0): Z = -2.25 P-Value = 0.024%3D%3DIs this a one-tailed or two-tailed test?a.b.What is the null hypothesis?Can Họ be rejected at the 5% level? How can you tell?C.

a. From the output, it observed that the alternative hypothesis has “≠” symbol. Therefore, it is…

Answered: The following MINITAB output presents…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The yield per tract in a certain region of farmland is known to have a populationstandard deviation of 13 bushels. Using the old seed variety, the population mean yield μwas 39 bushels. A farmer tests a new seed variety on a random sample of 36 tracts, andfinds a sample mean yield of 45.2 bushels. Is the population mean yield using the newseed variety different from 39? Use α= 0.10.a. State the null hypothesis . __________________State the alternative hypothesis.____________________b. Find the test statistic. _____ c. Find the P-value for the test. _____________
Molly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She obtains a random sample of 120 containers of ground beef and finds that 84 percent have the correct fat content. Molly then conducts a hypothesis test of H0:p=0.80H0:p=0.80 versus Ha:p≠0.80Ha:p≠0.80 and calculates a test statistic of 1.10 with a pp-value of 0.273. Which of the following best represents the meaning of the pp-value? If the population proportion is 0.84, the probability of observing a sample proportion of 0.80 is 0.273. A If the population proportion is 0.84, the probability of observing a sample proportion of at least 0.04 less than 0.84 is 0.273. B If the population proportion is 0.80, the probability of observing a sample proportion within 0.04 of 0.80 is 0.273. C If the population proportion is 0.80, the probability of observing a sample proportion at least 0.04 greater than 0.80 is 0.273. D If the…
The null and alternate hypotheses are: He: P₁ =H₂ H₁ H₁ #P₂ A random sample of 15 observations from the first population revealed a sample mean of 350 and a sample standard deviation of 12. A random sample of 17 observations from the second population revealed a sample mean of 342 and a sample standard deviation of 15. The population variances are assumed to be equal. At the 0.10 significance level, is there a difference in the population means? a. Is this a one-tailed or a two-tailed test? O One-tailed test. OTwo-tailed test. b. State the decision rule. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) The decision rule is to reject H0 if t
For each of the tests, what would be the conclusion if the test were carried out using the α = 0.05 level of significance? H0 : µ = 120, H1:µ ≠ 120, n = 36, S.D of population= 10.3, sample mean = 117.0
For the coefficient of an independent variable to be statistically significant and accepted as a valid estimate of the population coeficient, the prob. (or p-value) associated with the coefficient must be: O less than 0.01 O larger than 0.10 equal to or less than 0.05 O less than 1.00.
Suppose we have two normal populations denoted A and B, and we want to compare their population variances by estimating the ratio: variance of population B divided by variance of population A. We have an independent random sample of size 15 from population A and an independent random sample of size 9 from population B. The sample variance for population B turns out to be 30 percent larger than that for population A. What is the 99 percent confidence interval for the ratio: population variance of population B divided by population variance of population A? Use stattrek.org for finding the needed critical values.
I randomly sample 219 students and ask them to provide their USF GPA. I wish to determine if the average GPA of all USF students ex mu + 3.25 ceeds 3.25. Unfortunately, I generated the printout shown here: One-Sample T Test Null Hypothesis: H - 3.25 Alternative Hyp: u- 3.25 Variable Mean SE DF GPA 3.3121 0.0340 1.82 218 0.0694 Cases Included 219 What assumption is needed for this analysis to be valid? None. The Central Limit Theorem applies and no other assumptions are needed. The GPAS of all USF students need to be approximately normally distributed The mean GPA of all USF students need to be approximately normally distributed
A district sales manager wishes to determine whether there is a difference in mean daily sales volume between two stores in his district. He collects daily sales volume for the month of June to do the analysis. Assume that the population standard deviations are unknown and unequal. The hypothesis test is to be conducted using the 0.01 level of significance. Partial output of his results from Excel can be found in the table below: Store 1 Store 2 Sample size (n) 30 30 Sample mean daily sales volume (in $1,000) 15 19 Sample standard deviation (in $1,000) 5.2 6.1 Degrees of freedom 56 What is the critical value of the test statistic? Multiple Choice −1.645 ±1.960 ±2.667 ±2.395
Step 1 of 3. State the null and alternative hypotheses for the test. Step 2 of 3. Compute the value of the test statistic. Round your answer to three decimal places Step 3 of 3. Draw a conclusion and interpret the decision.
A two-sample z-test for two population proportions is to be performed using the P-value approach. The null hypothesis is Hn: P, = p, and the altemative is H: P, #p2. Use the given sample data to find the P-value for the hypothesis test. Give an Interpretation of the p-value. A state university found it lost 25 students out of 352 in 2013 and 36 students out of 334 in 2014. O A P-value = 0. 0455; There is about a 4.55% chance that the two proportions are equal. O B. P-value = 0.091; If there is no difference in the proportions, there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation. OC. P-value = 0.0455; there is no difference in the proportions, there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. O D. P-value = 0. 091; There is about a 9.1% chance that the two proportions are equal. O E. P-value = 0.9545: there is no difference in the proportions, there is about a 95.45% chance of…
How large should a sample be to estimate the population mean within [68.71, 71.29] with a 99% confidence interval if the sample mean is 70 and the population variance was 9 Select one: a. n= 26 b. n= 46 C. n= 16 O d. n= 36
The recidivism rate for convicted sex offenders is 12%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 322 convicted sex offenders who were also drug addicts, 48 of them became repeat offenders. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for a population proportion V b. The null and alternative hypotheses would be: Ho: ? v Select an answer (please enter a decimal) H1: ? v Select an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? V a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population proportion is not significantly different from 12% at a = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of…

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