The following MINITAB output presents the results of a hypothesis test for the differenceHx - Hy between two population means.Two-sample T for X vs YMeanStDevSE Mean1039.318.712.81029.124.791.5Difference = mu (X) – mu (Y)Estimate for difference: 10.197495% lower bound for difference: 4.6333T-Test of difference = 0 (vs >): T-Value = 3.25 P-Value = 0.003 DF = 13%3DIs this a one-tailed or two-tailed test?What is the null hypothesis?a.b.C.Can H, be rejected at the 1% level? How can you tell1?

a) Let µx and µy are the population mean of two populations. The hypotheses can be constructed as:…

Answered: The following MINITAB output presents…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Below is the complete question Fail to reject / reject H0. There is not / is enough evidence at the 1% level of significance to support / reject the claim.
Currently patrons at the library speak at an average of 61 decibels. Will this average decline after the installation of a new computer plug in station? After the plug in station was built, the librarian randomly recorded 57 people speaking at the library. Their average decibel level was 58 and their standard deviation was 10. What can be concluded at the the αα = 0.10 level of significance? For this study, we should use t-test for population mean The null and alternative hypotheses would be: H0:H0: Incorrect >, <, = or not equal to also provide the __?__ H1:H1: Incorrect >,<, = or not equal to also provide the __?__ The test statistic tc =(please show your answer to 3 decimal places.) The p-value = __?__ (Please show your answer to 4 decimal places.) e.Thus, the final conclusion is that .. a. The data suggest the populaton mean has significantly decreased from 61 at αα = 0.10, so there is statistically significant evidence…
The following data represent the length of time, in days, to recovery for patients randomly treated with one of two medications to clear up severe bladder infections. Find a 99% confidence interval for the difference µ, - H, between in the mean recovery times for the two medications, assuming normal populations with equal variances. Medication 1 n = = 10 x, = 17 = 1.9 Medication 2 n2 = 14 X2 = Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. = 19 S2 = 1.5 .... . The confidence interval is
Consider the following data on price ($) and the overall score for six stereo headphones tested by a certain magazine. The overall score is based on sound quality and effectiveness of ambient noise reduction. Scores range from 0 (lowest) to 100 (highest). Brand Price ($) Score 180 74 В 150 69 95 63 70 56 70 40 F 35 28 (a) The estimated regression equation for this data is ý = 25.870 + 0.291x, where x = price ($) and y = overall score. Does the t test indicate a significant relationship between price and the overall score? Use a = 0.05. State the null and alternative hypotheses. O Ho: Bo * 0 H: Bo = 0 O Ho: B1 20 Hoi Bq < 0 O Ho: Bo = 0 Hg: Bo 0 O Ho: B1* 0 H: B, = 0 O Ho: B, = 0 H: B1 = 0 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = What is your conclusion? O Do not reject H. We conclude that the relationship between price ($) and overall score is significant. O Do not reject…
The displays provided from the technology available below result from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 6.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistics, and P-value, and state the final conclusion that addresses the original claim. T-Test μ<6.00 t=−3.552993 p=0.000427 x=5.35 Sx=1.293612 n=50 Question content area bottom Part 1 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypothese
The specific gravities of a simple random sample of 91 samples of a particular wort has a mean x ̄ = 1.05 platos and a standard deviation sx = 0.16 platos. Use a 0.05 significance level to test the claim that the mean specific gravity of this wort is less than 1.10.
For the hypothesis test Ho: u = 14 against H1:µ < 14 and variance known, calculate the P-value for the following test statistic: Z0 = - 1.96. Round your answer to three decimal places (e.g. 98.765). P-value
Statistics Question
A researcher wishes to see if there is a difference between the mean number of hours per week that a family with no children participates in recreational activities and a family with children participates in recreational activities. She selects two random samples and the data are shown. Use μ1 for the mean number of families with no children. At α=0.10, is there a difference between the means? Use the P-value method and tables. (a) State the hypothesis and identify the claim with the correct hypothesis. H0: ▼(Choose one) H1: ▼(Choose one) This hypothesis test is a ▼(Choose one) test. (b)Find the critical value(s). Round the answer to 3decimal places, if necessary. If there ismore than one critical value, Critical values: (c)Compute the test value. Round the answer to at least 3 decimal places, if necessary. z= Compute the P -value. Round the answer to four decimal places. P-value= (d)Make the decision. What's the null hypothesis? (e)Summarize the…
ANOVA table is presented as: (a) (b) Source of Variation Factor A (Capping material) Factor B (Batch) Interaction (AB) Error (E) Total (T) SS 11573.38 17930.09 1734.17 4716.67 35954.31 Test all hypotheses from the ANOVA table using a 0.05 level of significance. Perform a pairwise comparison test using Fisher's LSD procedure using a 0.01 level of significance.
An NHANES report gives data for 647 women aged 20–29 years. The BMI of these 647 women was x= 25.8. On the basis of this sample, we want to estimate the BMI u in the population of all 20.6 million women in this age group. We treated these data as an SRS from a Normally distributed population with standard deviation o = 7.1. (a) Give three confidence intervals for the mcan BMI u in this population, using 90%, 95%, and 99% confidence. Enter the lower and upper bound for the 90% confidence interval. (Enter your answers rounded to two decimal places. If you are using Crunchlt, adjust the default precision under Preferences as necessary. See the instructional video on how to adjust precision scttings.) lower bound = uррer bound Enter the lower and upper bound for the 95% confidence interval. (Enter your answers rounded to two decimal places. If you are using Crunchlt, adjust the default precision under Preferences as necessary. See the instructional video on how to adjust precision…

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