Java The following method is designed to count the number of even numbers in an array.public int count Evens (int[] array) {return count EvensHelper (array, 0, array.length);}private int count EvensHelper(int[] array, int start, int stop) {int count = 0;if(start==stop) {return count;} else {}}if(array[start] % 2 == 0) {count = 1 + count EvensHelper (array, start+1, stop);}return count;Which of the following is true if the method is invoked with a non-empty array?The code is correct.none of these is correctThere is a compiler (syntax) error.The code will run, but there is a logical error.The code will run, but then will either crash or go into infinite recursion.

Introduction: A piece of code in given in Java, need to choose correct option Answer: The code will run, but there is a logical error Explanation: In the given code, there is a logical error. Every time code is returning 0. Recursion is being called when the number is even but there is no recursion call when number is odd Hence it is returning 0 every time. We need to add a recursion when number is odd. Modified Code: public static int coutEvens(int[] array) { return countEvensHelper(array, 0, array.length); } private static int countEvensHelper(int[] array, int start, int stop) { int count = 0; if(start == stop) { return count; } else { if(array[start]%2 == 0) { count = 1 + countEvensHelper(array, start +1, stop); } else { count = countEvensHelper(array, start +1, stop); } } return count; }