The following matrix A has a triple eigenvalue at A₁ = -1, and a single eigenvalue at A22. Compute its Jordan canonical form. A -1 0 -0.5 1 0 -1 0 -1 1 0 -0.25 -1.5 0.25 0.5 0 -1.5
The following matrix A has a triple eigenvalue at A₁ = -1, and a single eigenvalue at A22. Compute its Jordan canonical form. A -1 0 -0.5 1 0 -1 0 -1 1 0 -0.25 -1.5 0.25 0.5 0 -1.5
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![The following matrix \( A \) has a triple eigenvalue at \( \lambda_1 = -1 \), and a single eigenvalue at \( \lambda_2 = -2 \). Compute its Jordan canonical form.
\[
A = \begin{pmatrix}
-1 & 0 & -1 & 0 \\
0 & -1 & 1 & 0 \\
-0.5 & -0.25 & -1.5 & 0.25 \\
1 & 0.5 & 0 & -1.5
\end{pmatrix}.
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19556b7c-c5b6-4b4d-b523-18b6eba0d2d2%2F1a7e3232-52fe-4ff5-b77f-e0cafbaeedc5%2F7rdpecf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The following matrix \( A \) has a triple eigenvalue at \( \lambda_1 = -1 \), and a single eigenvalue at \( \lambda_2 = -2 \). Compute its Jordan canonical form.
\[
A = \begin{pmatrix}
-1 & 0 & -1 & 0 \\
0 & -1 & 1 & 0 \\
-0.5 & -0.25 & -1.5 & 0.25 \\
1 & 0.5 & 0 & -1.5
\end{pmatrix}.
\]
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Given that the following matrix A has a triple eigenvalue at and a single eigenvalue at
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