The following matrix A has a triple eigenvalue at A₁ = -1, and a single eigenvalue at A22. Compute its Jordan canonical form. A -1 0 -0.5 1 0 -1 0 -1 1 0 -0.25 -1.5 0.25 0.5 0 -1.5

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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The following matrix \( A \) has a triple eigenvalue at \( \lambda_1 = -1 \), and a single eigenvalue at \( \lambda_2 = -2 \). Compute its Jordan canonical form.

\[
A = \begin{pmatrix}
-1 & 0 & -1 & 0 \\
0 & -1 & 1 & 0 \\
-0.5 & -0.25 & -1.5 & 0.25 \\
1 & 0.5 & 0 & -1.5
\end{pmatrix}.
\]
Transcribed Image Text:The following matrix \( A \) has a triple eigenvalue at \( \lambda_1 = -1 \), and a single eigenvalue at \( \lambda_2 = -2 \). Compute its Jordan canonical form. \[ A = \begin{pmatrix} -1 & 0 & -1 & 0 \\ 0 & -1 & 1 & 0 \\ -0.5 & -0.25 & -1.5 & 0.25 \\ 1 & 0.5 & 0 & -1.5 \end{pmatrix}. \]
Expert Solution
Step 1

Given that the following matrix A has a triple eigenvalue at λ=-1,  and a single eigenvalue at λ2=-2.

                                           A=-10-100-110-0.5-0.25-1.50.2510.50-1.5.

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