The following LP formulation represents a transportation problem where raw material (in tons) is transported from Supplier i, i={1,2,3) to Plant j, j={1,2,3). The problem is solved and the optimal objective function value is 5200. Using the sensitivity report shown below, what would be the optimal total cost if the cost of transporting 1 ton from Supplier 2 to Plant 3 becomes 5? Min Total cost = 1x11 + 3x12 + 5x13+3.5x21 +4x22+4.8x23 +3.5x31+3.6x32 +3.2x33 Subiect to
The following LP formulation represents a transportation problem where raw material (in tons) is transported from Supplier i, i={1,2,3) to Plant j, j={1,2,3). The problem is solved and the optimal objective function value is 5200. Using the sensitivity report shown below, what would be the optimal total cost if the cost of transporting 1 ton from Supplier 2 to Plant 3 becomes 5? Min Total cost = 1x11 + 3x12 + 5x13+3.5x21 +4x22+4.8x23 +3.5x31+3.6x32 +3.2x33 Subiect to
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:The following LP formulation represents a transportation problem where raw material (in tons) is transported from Supplier i, i={1,2,3) to
Plant j, j={1,2,3). The problem is solved and the optimal objective function value is 5200. Using the sensitivity report shown below, what
would be the optimal total cost if the cost of transporting 1 ton from Supplier 2 to Plant 3 becomes 5?
Min Total cost = 1x11 + 3x12 + 5x13+3.5x21 +4x22+4.8x23 +3.5x31+3.6x32 +3.2x33
Subject to
x31+x32+x33 <= 500
x11+x21+x31 = 500
x12+x22+x32= 700
x13+x23+x33 = 600
xij<=200, for i= {2,3}
&j= {1, 2, 3)
xij >= 0, for i= {(1,2,3)
X
&j= {1, 2, 3)
Final Reduced Objective Allowable Allowable
Name
Value
Cost Coefficient Increase Decrease
500
0
1
2.5
1E+30
700
0
3
0.6
1E+30
0.2
200
5
0
2.5
1E+30
1E+30
1E+30
0.2
1E+30
1
IE+30
2.5
1E+30
0.6
1E+30
1.8
Variables
X11
X12
X13
X21
X22
X23
X31
X32
X33
0
200
0
0
200
0
0
0
0
0
0
0
3.5
4
4.8
3.5
3.6
3.2
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