The following iterative sequence is defined for the set of positive integers: Sn/5 n-2 ifn is odd if n is a multiple of 5 Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 11- =9 ug = 7 u7 =5 Us =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 6 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq(n) %3D %3D
The following iterative sequence is defined for the set of positive integers: Sn/5 n-2 ifn is odd if n is a multiple of 5 Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 11- =9 ug = 7 u7 =5 Us =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 6 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq(n) %3D %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:The following iterative sequence is defined for the set of positive integers:
Sn/5 if n is a multiple of 5
|n-2 if n is odd
Using the rule above and starting with 13, we generate the following sequence:
13 → u13 = 11 - u11 =9 ug = 7uz =5 us =1.
It can be seen that this sequence (starting at 13 and finishing at 1) contains 6 terms.
The below function takes as input an integer n and returns the number of terms
generated by the sequence starting at n.
function i-Seq(n)
%3D
%3D
%3D
; מיט
i=13;
while u-1
if statement 1
u=u/5
else
statement 2
end
i=i+1;
end
statement 1 and statement 2 should be replaced by:
Statement 1 is "mod(u,5)==0" and
statement 2 is "u = n-2;"
None of the choices
Statement 1 is "n%5==0" and statement 2 is
"u = u-2;"
Statement 1 is "mod(u,5)==0" and
statement 2 is "u = u-2;"
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