The following is the brief summary of how Aliquot 1 was prepared in Expt. 8: Step 1: The unknown stock solution was prepared by dissolving 0.5079 g of a steel sample, yielding 200.0 ml of the solution. • Step 2: Aliquat 1 was prepared by diluting 25.00 ml of the unknown stock solution to 50.00 ml. if the concentration of Mn In Aliquot 1 ([X]) is 4.81 x 105 M, what would be the wt% of Mn2 in the unknown steel sample.

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter18: Representative Metals, Metalloids, And Nonmetals
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Problem 116E: Basic solutions of Na4XeO6, are powerful oxidants. What mass of Mn(NO3)26H2O reacts with 125.0 mL of...
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The following is the brief summary of how Aliquot 1 was prepared in Expt. 8:
Step 1: The unknown stock solution was prepared by dissolving 0.5079 g of a steel sample, yielding 200.0 ml of the solution.
• Step 2: Aliquat 1 was prepared by diluting 25.00 ml of the unknown stock solution to 50.00 ml.
if the concentration of Mn2 In Aliquot 1 [[X]) is 4.81 x 105 M, what would be the wt% of Mn2" in the unknown steel sample.
O 0.595 %
0.135 %
0206%
O 0.439 %
O.0.376%
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Transcribed Image Text:Chemistry The following is the brief summary of how Aliquot 1 was prepared in Expt. 8: Step 1: The unknown stock solution was prepared by dissolving 0.5079 g of a steel sample, yielding 200.0 ml of the solution. • Step 2: Aliquat 1 was prepared by diluting 25.00 ml of the unknown stock solution to 50.00 ml. if the concentration of Mn2 In Aliquot 1 [[X]) is 4.81 x 105 M, what would be the wt% of Mn2" in the unknown steel sample. O 0.595 % 0.135 % 0206% O 0.439 % O.0.376% mit Quiz
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