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The following is another student's solution to a kinematics problem. Describe two possible questions they could have been responding to. Vertically: งาม = 13.0) sin37° = 7.824m/s - S ay = -9.8 m/s² dy = 2.0 m Using the vertical component to find time. dy = vist + a(t)² 2 2.0 m = (7.824) (t) 9.8) (t) 2 2 0 = (4.9)t2 (7.824)t + 2.0 - t Horizontally: -bb2-4ac t = 2a 7.824±√(-7.824)² - 4(4.9)(2.0) 2(4.9) t = 1.277 s or 0.3196 s Vx = (13.0) co cos37° 10.38m/s dx Vx = t dx dx = vxt 13.2 m

The following is another student's solution to a kinematics problem. Describe two possible questions they could have been responding to. Vertically: งาม = 13.0) sin37° = 7.824m/s - S ay = -9.8 m/s² dy = 2.0 m Using the vertical component to find time. dy = vist + a(t)² 2 2.0 m = (7.824) (t) 9.8) (t) 2 2 0 = (4.9)t2 (7.824)t + 2.0 - t Horizontally: -bb2-4ac t = 2a 7.824±√(-7.824)² - 4(4.9)(2.0) 2(4.9) t = 1.277 s or 0.3196 s Vx = (13.0) co cos37° 10.38m/s dx Vx = t dx dx = vxt 13.2 m

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The following is another student's solution to a kinematics problem. Describe two possible questions they could have been responding to. Vertically: งาม = 13.0) sin37° = 7.824m/s - S ay = -9.8 m/s² dy = 2.0 m Using the vertical component to find time. dy = vist + a(t)² 2 2.0 m = (7.824) (t) 9.8) (t) 2 2 0 = (4.9)t2 (7.824)t + 2.0 -
Transcribed Image Text:The following is another student's solution to a kinematics problem. Describe two possible questions they could have been responding to. Vertically: งาม = 13.0) sin37° = 7.824m/s - S ay = -9.8 m/s² dy = 2.0 m Using the vertical component to find time. dy = vist + a(t)² 2 2.0 m = (7.824) (t) 9.8) (t) 2 2 0 = (4.9)t2 (7.824)t + 2.0 -
t Horizontally: -bb2-4ac t = 2a 7.824±√(-7.824)² - 4(4.9)(2.0) 2(4.9) t = 1.277 s or 0.3196 s Vx = (13.0) co cos37° 10.38m/s dx Vx = t dx dx = vxt 13.2 m
Transcribed Image Text:t Horizontally: -bb2-4ac t = 2a 7.824±√(-7.824)² - 4(4.9)(2.0) 2(4.9) t = 1.277 s or 0.3196 s Vx = (13.0) co cos37° 10.38m/s dx Vx = t dx dx = vxt 13.2 m
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