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The following is an example of a(n) HC-OH NADH O addition O reduction O hydrolysis O oxidation over . ܗܝ.ܞܦܗ CR HCH NAD H₂O reaction.

The following is an example of a(n) HC-OH NADH O addition O reduction O hydrolysis O oxidation over . ܗܝ.ܞܦܗ CR HCH NAD H₂O reaction.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**The following is an example of a(n) ____________ reaction:** \[ \text{HC(OH) + NADH} \xrightarrow{\text{CR}} \text{HCH + NAD}^+ \text{ + H}_2\text{O} \] *Options:* - Addition - Reduction - Hydrolysis - Oxidation - Over **Explanation:** In this chemical equation, an alcohol group (–OH) is oxidized to an aldehyde (–CHO). Additionally, NADH is oxidized to NAD⁺. This type of reaction is an example of an oxidation reaction. Select the correct answer by choosing the radiobutton next to "oxidation."
Transcribed Image Text:**The following is an example of a(n) ____________ reaction:** \[ \text{HC(OH) + NADH} \xrightarrow{\text{CR}} \text{HCH + NAD}^+ \text{ + H}_2\text{O} \] *Options:* - Addition - Reduction - Hydrolysis - Oxidation - Over **Explanation:** In this chemical equation, an alcohol group (–OH) is oxidized to an aldehyde (–CHO). Additionally, NADH is oxidized to NAD⁺. This type of reaction is an example of an oxidation reaction. Select the correct answer by choosing the radiobutton next to "oxidation."
**Oxidation State of Carbon in Organic Compounds** **Question:** What is the oxidation state on the central carbon in the following compound? **Compound:** ``` H- C H | | H3CO C OH ``` **Options:** - 0 - +1 - +2 - +3 - +4 **Explanation:** To determine the oxidation state of the central carbon atom in the compound, follow these steps: 1. **Assign known oxidation states:** - Hydrogen (H) typically has an oxidation state of +1. - Oxygen (O) typically has an oxidation state of -2. 2. **Write down the oxidation state for each element:** - The central carbon (C) is bonded to two hydrogen atoms, one hydroxyl group (OH), and one methoxy group (H3CO). 3. **Calculate the oxidation state of the central carbon (C):** - Let \( x \) be the oxidation state of the central carbon. - The total oxidation state for a neutral molecule should be 0. 4. **Set up the equation:** - For each hydrogen attached to the central carbon: \( 2(+1) \) (as there are two hydrogens). - The oxidation state of oxygen in OH group is -2, and in H3CO group oxygen also contributes -2. - The methoxy group (CH3O-) can be considered to have the carbon (-3), three hydrogen (+3 in total), and one oxygen (-2). The equation based on the compound should balance: \[ x + 1 + 1 + (-2) + (-2) = 0 \] Simplify and solve: \[ x + 2 - 4 = 0 \implies x-2 = 0 \implies x = +2 \] **Correct Answer:** - +2
Transcribed Image Text:**Oxidation State of Carbon in Organic Compounds** **Question:** What is the oxidation state on the central carbon in the following compound? **Compound:** ``` H- C H | | H3CO C OH ``` **Options:** - 0 - +1 - +2 - +3 - +4 **Explanation:** To determine the oxidation state of the central carbon atom in the compound, follow these steps: 1. **Assign known oxidation states:** - Hydrogen (H) typically has an oxidation state of +1. - Oxygen (O) typically has an oxidation state of -2. 2. **Write down the oxidation state for each element:** - The central carbon (C) is bonded to two hydrogen atoms, one hydroxyl group (OH), and one methoxy group (H3CO). 3. **Calculate the oxidation state of the central carbon (C):** - Let \( x \) be the oxidation state of the central carbon. - The total oxidation state for a neutral molecule should be 0. 4. **Set up the equation:** - For each hydrogen attached to the central carbon: \( 2(+1) \) (as there are two hydrogens). - The oxidation state of oxygen in OH group is -2, and in H3CO group oxygen also contributes -2. - The methoxy group (CH3O-) can be considered to have the carbon (-3), three hydrogen (+3 in total), and one oxygen (-2). The equation based on the compound should balance: \[ x + 1 + 1 + (-2) + (-2) = 0 \] Simplify and solve: \[ x + 2 - 4 = 0 \implies x-2 = 0 \implies x = +2 \] **Correct Answer:** - +2
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