The following is a control chart for the average number of minor errors in 22 service reports.UCLLCLa. Calculate the observed mean, expected mean, standard deviation and z value for the median and up/down test. Use z = +/-2 tocompare your z test scores. (Negative amounts should be indicated by a minus sign. Round your answers to 2 decimal places.)TestObservedExpectedStd. devMedianUp/Down

Answered: The following is a control chart for…

Practical Management Science

6th Edition

ISBN:9781337406659

Author:WINSTON, Wayne L.

Publisher:WINSTON, Wayne L.

Chapter2: Introduction To Spreadsheet Modeling

Section: Chapter Questions

Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...

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The school board is trying to evaluate a new math program introduced to second-graders in five elementary schools across the county this year. A sample of the student scores onstandardized math tests in each elementary school yielded the following data: Construct a c-chart for test errors, and set the control limits to con tain 99 .73% of the random variation in test scores. What does the chart tell you? Has the new math program been effective?
hw3q1
Do control charts assist in monitoring quality as conformance or quality as improvement?
Boxes of Honey-Nut Oatmeal are produced to contain 14.0 ounces, with a standard deviation of 0.10 ounce. For a sample size of 49, the 3-sigma x chart control limits are: Upper Control Limit (UCL) = Lower Control Limit (LCL) = ounces (round your response to two decimal places). ounces (round your response to two decimal places).
C-Spec, Incorporated is attempting to determine whether an existing machine is capable of milling an engine part that has a key specification of 4 ± 0.003 inch. After a trial run on this machine, C-Spec has determined that the machine has a sample mean of 4.001 inches with a standard deviation of 0.002 inch. Calculate the capability index ( Cpk�� ) for this machine. Note: Round your answer to 3 decimal places. Should C-Spec use this machine to produce this part? multiple choice Yes No
Distinguish between a sampling error and a nonsampling error.How can each be reduced?
2) The specification for a Lindemann’s stainless steel chimney liner requires a thickness of 7.1 mm ± 0.1 mm. The firm’s quality analyst determines that the liner process operates at a mean thickness of 7.13 mm with the standard deviation of the process being 0.02 mm. a) Calculate the upper and the lower limits for the stainless steel chimney liner. b) Calculate the Cpand Cpkfor this process. Hint: Cp = (Upper Specification Limit – Lower Specification Limit)/6sigma Cpk = minimum of [(Upper Specification Limit – Xbar)/3sigma], [(Xbar – Lower Specification Limit)/3sigma]
A shirt manufacturer buys clothes by the 100-yard roll from a supplier. For setting a control chart to manage the irregularities (e.g., loose threads and tears), the following data were collected from a sample provided by the supplier. Sample 1 2 3 4 5 6 7 8 9 10 Irregularities 3 5 2 6 5 4 6 3 4 5 Which type of control chart should be used? Construct a control chart with two-sigma control limits. Suppose the next five rolls from the supplier had three, two, five, three, and seven irregularities. Is the supplier process under control? Explain and show work
A microbrewery tracks its output in gallons over a five hour period for each of seven days. Their data is in the table below, and they went ahead and calculated the averages and ranges for the individual samples and the overall averages Their data and the factors tables can be found below. Calculate the upper (LCL) and lower (UCL) control limits for X bar, and R charts for their process. Day (X values) X̅ R 1 46 49 45 47 48 47.0 4 2 43 52 46 52 44 47.4 9 3 45 55 46 51 43 48.0 12 4 39 44 42 43 40 41.6 5 5 45 50 48 50 42 47.0 8 6 44 48 45 45 40 44.4 8 7 41 44 52 50 47 46.8 11 X̿ = 46.03 R̅ 8.14 Xbar chart - LCL = 40.48, UCL=46.25, R chart LCL=0, UCL=14.01 Xbar chart - LCL = 44.21, UCL=48.41, R chart LCL=0.49, UCL=17.18 Xbar chart - LCL = 42.61, UCL=49.45, R chart LCL=0.65, UCL=15.63 Xbar chart - LCL = 44.21, UCL=51.62, R chart LCL=0, UCL=17.18 Xbar chart - LCL = 41.31, UCL=50.75, R chart LCL=0, UCL=17.18
Refer to Table 56.1-Factors for Computing Control Chart Limits.(3.sigma) for this problem. Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: a) What is the value of x? mm (round your response to two decimal places). b) What is the value of R? R=mm (round your response to two decimal places). c) What are the UCL, and LCL; using 3-sigma? Day 1 2 3 4 5 Upper Control Limit (UCL;)mm (round your response to two decimal places) Lower Control Limit (LCL;)mm (round your response to two decimal places). d) What are the UCL and LCL using 3-sigma? Upper Control Limit (UCLR)-mm (round your response to two decimal places). Lower Control Limit (LCL)-mm (round your response to two decimal places) Mean x (mm) 154.9 151.2 155.6 155.5 154.6 Range R (mm) 4.4 4.8 4.3 5.0 4.7 Next

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