The following integral can be evaluated by using substitution: a) Identify the inside function. u= x^5-1 z³-1✔ Differentiate: 5x^4 524 Make dz the subject: dz = 1/(5x^4) du b) Rewrite the whole integral in terms of u and du: -du 524 X [22ª sin (2³-1) dz 2x^4sin(u) Simplify and cancel 's: 2/5 sin(u) sin(u) ✔du Integrate with respect to u: du 5x^4

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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help me in part B where i got wrong.

The following integral can be evaluated by using substitution:
a)
b)
Identify the inside function, u = X^5-1 T³ - 1 ✔
Differentiate:
5x^4 5x²
Make dr the subject: dx = 1/(5x^4) du
Simplify and cancel z's: 2/5 sin(u)
Integrate with respect to u:
Rewrite the whole integral in terms of u and du: 2x^4sin(u)
X
1
5x
25
du
[2.rª sin (25 - 1) dr
sin(u) du
du
5x^4
Transcribed Image Text:The following integral can be evaluated by using substitution: a) b) Identify the inside function, u = X^5-1 T³ - 1 ✔ Differentiate: 5x^4 5x² Make dr the subject: dx = 1/(5x^4) du Simplify and cancel z's: 2/5 sin(u) Integrate with respect to u: Rewrite the whole integral in terms of u and du: 2x^4sin(u) X 1 5x 25 du [2.rª sin (25 - 1) dr sin(u) du du 5x^4
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