The following integral can be evaluated by using substitution: a) Identify the inside function. u= x^5-1 z³-1✔ Differentiate: 5x^4 524 Make dz the subject: dz = 1/(5x^4) du b) Rewrite the whole integral in terms of u and du: -du 524 X [22ª sin (2³-1) dz 2x^4sin(u) Simplify and cancel 's: 2/5 sin(u) sin(u) ✔du Integrate with respect to u: du 5x^4
The following integral can be evaluated by using substitution: a) Identify the inside function. u= x^5-1 z³-1✔ Differentiate: 5x^4 524 Make dz the subject: dz = 1/(5x^4) du b) Rewrite the whole integral in terms of u and du: -du 524 X [22ª sin (2³-1) dz 2x^4sin(u) Simplify and cancel 's: 2/5 sin(u) sin(u) ✔du Integrate with respect to u: du 5x^4
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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help me in part B where i got wrong.
![The following integral can be evaluated by using substitution:
a)
b)
Identify the inside function, u = X^5-1 T³ - 1 ✔
Differentiate:
5x^4 5x²
Make dr the subject: dx = 1/(5x^4) du
Simplify and cancel z's: 2/5 sin(u)
Integrate with respect to u:
Rewrite the whole integral in terms of u and du: 2x^4sin(u)
X
1
5x
25
du
[2.rª sin (25 - 1) dr
sin(u) du
du
5x^4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3afc900a-c718-4e75-9668-b877cac7e5e5%2F40ccf3f3-848c-4260-bb8a-d3560c61ac2f%2F8vzxpns_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The following integral can be evaluated by using substitution:
a)
b)
Identify the inside function, u = X^5-1 T³ - 1 ✔
Differentiate:
5x^4 5x²
Make dr the subject: dx = 1/(5x^4) du
Simplify and cancel z's: 2/5 sin(u)
Integrate with respect to u:
Rewrite the whole integral in terms of u and du: 2x^4sin(u)
X
1
5x
25
du
[2.rª sin (25 - 1) dr
sin(u) du
du
5x^4
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