The following information is given for water at 1 atm: AHvap (100.00°C) = 2.259 × 10³ J/g AĦfus (0.00°C) = 333.5 J/g T, = 100.00°C Tm = 0.00°C Specific heat solid = 2.100 J/g °C Specific heat liquid = 4.184 J/g °C A 38.10 g sample of solid water is initially at -15.00°C. If the sample is heated at constant pressure (P = 1 atm), kJ of heat are needed to raise the temperature of the sample to 27.00°C.

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**References**

Use the References to access important values if needed for this question.

The following information is given for water at 1 atm:

- **Boiling point (T_b)**: 100.00°C
- **Melting point (T_m)**: 0.00°C
- **Heat of vaporization (ΔH_vap at 100.00°C)**: 2.259 × 10³ J/g
- **Heat of fusion (ΔH_fus at 0.00°C)**: 333.5 J/g
- **Specific heat of solid water (ice)**: 2.100 J/g°C
- **Specific heat of liquid water**: 4.184 J/g°C

**Problem Statement:**

A 38.10 g sample of solid water (ice) is initially at -15.00°C. If the sample is heated at constant pressure (P = 1 atm), how many kJ of heat are needed to raise the temperature of the sample to 27.00°C?

To calculate the total heat required, you need to account for the following steps:
1. Heating the ice from -15.00°C to 0.00°C.
2. Melting the ice at 0.00°C.
3. Heating the liquid water from 0.00°C to 27.00°C. 

You can use the following formulas for each step:

1. **Heating the ice:**
\[ q_1 = m \times c_{\text{solid}} \times \Delta T_1 \]
where:
- \( q_1 \) = heat required to raise the temperature of ice,
- \( m \) = mass of the sample,
- \( c_{\text{solid}} \) = specific heat of solid water,
- \( \Delta T_1 \) = change in temperature (final temperature - initial temperature).

2. **Melting the ice:**
\[ q_2 = m \times \Delta H_{\text{fus}} \]
where:
- \( q_2 \) = heat required to melt the ice,
- \( \Delta H_{\text{fus}} \) = heat of fusion.

3. **Heating the liquid water:**
\[ q_3 = m \times c_{\text{liquid}} \times \Delta T_2 \]
where:
- \( q_3 \) = heat required to raise the temperature
Transcribed Image Text:**References** Use the References to access important values if needed for this question. The following information is given for water at 1 atm: - **Boiling point (T_b)**: 100.00°C - **Melting point (T_m)**: 0.00°C - **Heat of vaporization (ΔH_vap at 100.00°C)**: 2.259 × 10³ J/g - **Heat of fusion (ΔH_fus at 0.00°C)**: 333.5 J/g - **Specific heat of solid water (ice)**: 2.100 J/g°C - **Specific heat of liquid water**: 4.184 J/g°C **Problem Statement:** A 38.10 g sample of solid water (ice) is initially at -15.00°C. If the sample is heated at constant pressure (P = 1 atm), how many kJ of heat are needed to raise the temperature of the sample to 27.00°C? To calculate the total heat required, you need to account for the following steps: 1. Heating the ice from -15.00°C to 0.00°C. 2. Melting the ice at 0.00°C. 3. Heating the liquid water from 0.00°C to 27.00°C. You can use the following formulas for each step: 1. **Heating the ice:** \[ q_1 = m \times c_{\text{solid}} \times \Delta T_1 \] where: - \( q_1 \) = heat required to raise the temperature of ice, - \( m \) = mass of the sample, - \( c_{\text{solid}} \) = specific heat of solid water, - \( \Delta T_1 \) = change in temperature (final temperature - initial temperature). 2. **Melting the ice:** \[ q_2 = m \times \Delta H_{\text{fus}} \] where: - \( q_2 \) = heat required to melt the ice, - \( \Delta H_{\text{fus}} \) = heat of fusion. 3. **Heating the liquid water:** \[ q_3 = m \times c_{\text{liquid}} \times \Delta T_2 \] where: - \( q_3 \) = heat required to raise the temperature
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