The following information is given for antimony at latm: AHvap (1440.00°C) = 1.605 × 10° J/g AHfi1s (631.00°C) = 161.1 J/g T, = 1440.00°C Tm = 631.00°C Specific heat solid = 0.2090 J/g °C Specific heat liquid = 0.2590 J/g °C A 42.60 g sample of liquid antimony at 720.00°C is poured into a mold and allowed to cool to 27.00°C. How many kJ of energy are released in this process? (Report the answer as a positive number.) Energy |kJ

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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The following information is given for antimony at latm:
AHvap (1440.00°C) = 1.605 x 10 J/g
ДНis (631.00°C) - 161.1 J/g
Ть — 1440.00°С
Tm = 631.00°C
Specific heat solid = 0.2090 J/g °C
Specific heat liquid = 0.2590 J/g °C
A 42.60 g sample of liquid antimony at 720.00°C is poured into a mold and allowed to cool to 27.00°C. How many kJ of energy are released
process?
this
(Report the answer as a positive number.)
Energy =
kJ
Transcribed Image Text:The following information is given for antimony at latm: AHvap (1440.00°C) = 1.605 x 10 J/g ДНis (631.00°C) - 161.1 J/g Ть — 1440.00°С Tm = 631.00°C Specific heat solid = 0.2090 J/g °C Specific heat liquid = 0.2590 J/g °C A 42.60 g sample of liquid antimony at 720.00°C is poured into a mold and allowed to cool to 27.00°C. How many kJ of energy are released process? this (Report the answer as a positive number.) Energy = kJ
Expert Solution
Step 1

First,the liquid antimony cools from 720 °C to 631 °C. Since the specific heat for the liquid is 0.2590 J/g °C this heat is                        E = m × C × Δ t            where  m  is the mass,                        C  is the specific heat            and  Δ t  is the temperature change.                 E = 42.60  g × 0.2590  Jg ° C × (720-631)° C                   = 981.9726 J  

 

 

 

 

 

 

 

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