The following information is given for aluminum at 1 atm: T=2467.00°C Tm=660.00°C Specific heat solid = 0.9000 Specific heat liquid = 1.088 A 42.30 g sample of solid aluminum is initially at 640.00°C. If the sample is heated at constant pressure (P = 1 atm), of the sample to 1030 00°C g. °C AHvap (2467.00° C) = 10530 J/g AHfus (660.00°C) = 398.4 J/g kJ of heat are needed to raise the temperature

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The following information is given for aluminum at 1 atm:
T= 2467.00°C
Tm=660.00°C
Specific heat solid = 0.9000
Specific heat liquid = 1.088
A 42.30 g sample of solid aluminum is initially at 640.00°C. If the sample is heated at constant pressure (P = 1 atm),
of the sample to 1030.00°C.
J
g. °C
J
g.°C
AHvap (2467.00° C) = 10530 J/g
AHfus (660.00° C) = 398.4 J/g
kJ of heat are needed to raise the temperature
Transcribed Image Text:The following information is given for aluminum at 1 atm: T= 2467.00°C Tm=660.00°C Specific heat solid = 0.9000 Specific heat liquid = 1.088 A 42.30 g sample of solid aluminum is initially at 640.00°C. If the sample is heated at constant pressure (P = 1 atm), of the sample to 1030.00°C. J g. °C J g.°C AHvap (2467.00° C) = 10530 J/g AHfus (660.00° C) = 398.4 J/g kJ of heat are needed to raise the temperature
Expert Solution
Step 1

Given,

The melting point of Al = 660.0 °C

Initial temperature = 640.0°C

Final temperature =  1030.00 °C

Mass of sample = 42.30 g

Heat requires can be calculated by 

Q = m.S.TWhere S = specific heat of sample m = mass of sample

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