The following holds marginal pdf of X P(X > 3) = re-#(1+y) dy dx = xe-". e¬#" dy dx e¬ª dx = 0.05.

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ISBN:9780470458365
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Chapter2: Second-order Linear Odes
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Please explain the calculus portion of the attached screen shot without assuming too much. Thank you.

In this educational excerpt, the process of computing the probability by integrating a joint probability density function (pdf) is discussed. The text explains two methods to compute the probability: either compute the marginal pdf of \( X \) first and then find \( X > 3 \) using the marginal pdf, or compute it directly. The focus here is on the second method, which is indirect.

The integral equation is presented as:

\[ 
P[(X,Y) \in A] = \int_A \int f(x,y) \, dx \, dy 
\]

In this context, for a set \( A \), the above equation holds. 

The main focus is on calculating \( P(X > 3) \) given by:

\[
P(X > 3) = \int_3^{\infty} \left( \int_0^{\infty} xe^{-x(1+y)} \, dy \right) \, dx = \int_3^{\infty} \left( \int_0^{\infty} xe^{-x} \cdot e^{-xy} \, dy \right) \, dx 
\]

This simplifies through a series of steps involving integration:

1. First, the inner integral with respect to \( y \) is solved.
2. This yields a factor involving \( e^{-x} \).
3. The remaining integration over \( x \) results in evaluating an exponential function's limit.

The final result of the computation is:

\[
P(X > 3) = e^{-3} = 0.05
\]

This result denotes that the probability of \( X \) being greater than 3 is 0.05.

The explanation includes boxed content highlighting key information from the calculation, emphasizing the final probability value of 0.05.
Transcribed Image Text:In this educational excerpt, the process of computing the probability by integrating a joint probability density function (pdf) is discussed. The text explains two methods to compute the probability: either compute the marginal pdf of \( X \) first and then find \( X > 3 \) using the marginal pdf, or compute it directly. The focus here is on the second method, which is indirect. The integral equation is presented as: \[ P[(X,Y) \in A] = \int_A \int f(x,y) \, dx \, dy \] In this context, for a set \( A \), the above equation holds. The main focus is on calculating \( P(X > 3) \) given by: \[ P(X > 3) = \int_3^{\infty} \left( \int_0^{\infty} xe^{-x(1+y)} \, dy \right) \, dx = \int_3^{\infty} \left( \int_0^{\infty} xe^{-x} \cdot e^{-xy} \, dy \right) \, dx \] This simplifies through a series of steps involving integration: 1. First, the inner integral with respect to \( y \) is solved. 2. This yields a factor involving \( e^{-x} \). 3. The remaining integration over \( x \) results in evaluating an exponential function's limit. The final result of the computation is: \[ P(X > 3) = e^{-3} = 0.05 \] This result denotes that the probability of \( X \) being greater than 3 is 0.05. The explanation includes boxed content highlighting key information from the calculation, emphasizing the final probability value of 0.05.
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