The following formula is used to calculate the wind chill factor W in degree Celsius. (10.45 + 10 V - V) (33 –* $3- T) W = 33 – 22.04 T is the air temperature in degree Celsius and V is the wind speed in meters per second. Use the formulas to the right as needed. (a) Determine the wind chill for an air temperature of 4°C and a wind speed of 24 meters per second. (b) Determine the wind chill for an air temperature of 27°F and a wind speed of 26 mph. Convert your final answer to degrees Fahrenheit.
The following formula is used to calculate the wind chill factor W in degree Celsius. (10.45 + 10 V - V) (33 –* $3- T) W = 33 – 22.04 T is the air temperature in degree Celsius and V is the wind speed in meters per second. Use the formulas to the right as needed. (a) Determine the wind chill for an air temperature of 4°C and a wind speed of 24 meters per second. (b) Determine the wind chill for an air temperature of 27°F and a wind speed of 26 mph. Convert your final answer to degrees Fahrenheit.
Algebra and Trigonometry (6th Edition)
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![### Wind Chill Calculation
The following formula is used to calculate the wind chill factor \( W \) in degrees Celsius:
\[ W = 33 - \frac{(10.45 + 10\sqrt{V} - V)(33 - T)}{22.04} \]
- \( T \) is the air temperature in degrees Celsius.
- \( V \) is the wind speed in meters per second.
Use the formulas to the right as needed:
\[
^\circ C = \frac{5(^\circ F - 32)}{9} \\
^\circ F = \frac{9^\circ C}{5} + 32
\]
Conversion factors:
- 1 mile = 1609.344 meters
- 1 hour = 3600 seconds
### Tasks
(a) **Determine the wind chill for an air temperature of 4°C and a wind speed of 24 meters per second.**
\[ \text{The wind chill is } \_\_\_ ^\circ C. \]
*(Round the final answer to the nearest tenth as needed. Round all intermediate values to the nearest tenth as needed.)*
(b) **Determine the wind chill for an air temperature of 27°F and a wind speed of 26 mph. Convert your final answer to degrees Fahrenheit.**
\[ \text{The wind chill is } \_\_\_ ^\circ F. \]
*(Round the final answer to the nearest tenth as needed. Round all intermediate values to the nearest tenth as needed.)*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F417947df-9deb-419b-ad5d-7cb535a2c93f%2F90045a7c-2b57-477a-8603-fd8379986f20%2Fbovsbjg_processed.png&w=3840&q=75)
Transcribed Image Text:### Wind Chill Calculation
The following formula is used to calculate the wind chill factor \( W \) in degrees Celsius:
\[ W = 33 - \frac{(10.45 + 10\sqrt{V} - V)(33 - T)}{22.04} \]
- \( T \) is the air temperature in degrees Celsius.
- \( V \) is the wind speed in meters per second.
Use the formulas to the right as needed:
\[
^\circ C = \frac{5(^\circ F - 32)}{9} \\
^\circ F = \frac{9^\circ C}{5} + 32
\]
Conversion factors:
- 1 mile = 1609.344 meters
- 1 hour = 3600 seconds
### Tasks
(a) **Determine the wind chill for an air temperature of 4°C and a wind speed of 24 meters per second.**
\[ \text{The wind chill is } \_\_\_ ^\circ C. \]
*(Round the final answer to the nearest tenth as needed. Round all intermediate values to the nearest tenth as needed.)*
(b) **Determine the wind chill for an air temperature of 27°F and a wind speed of 26 mph. Convert your final answer to degrees Fahrenheit.**
\[ \text{The wind chill is } \_\_\_ ^\circ F. \]
*(Round the final answer to the nearest tenth as needed. Round all intermediate values to the nearest tenth as needed.)*
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