The following equations are also quadratic in form. To solve, begin by raising each side of the equation to the appropriate power so that the exponent will become an integer. Then, to solve the resulting quadratic equation, you may use the square-root property, factoring, or the quadratic formula—whichever is most appropriate. Be aware that raising each side of the equation to a power may introduce extraneous roots; therefore, be sure to check your solutions. Study the following example before you begin the problems.Solve(x + 3)2/3 = 1[(x + 3)2/3]3 = 13(x + 3)2 = 1x2 + 6x + 9 = 1x2 + 6x + 8 = 0(x + 4)(x + 2) = 0x + 4 = 0 or x + 2 = 0x = -4 or x = -2Both solutions do check. The solution set is {-4, -2}. solve each equation. [2x - 4]2/3 = 1
The following equations are also quadratic in form. To solve, begin by raising each side of the equation to the appropriate power so that the exponent will become an integer. Then, to solve the resulting quadratic equation, you may use the square-root property, factoring, or the quadratic formula—whichever is most appropriate. Be aware that raising each side of the equation to a power may introduce extraneous roots; therefore, be sure to check your solutions. Study the following example before you begin the problems.Solve(x + 3)2/3 = 1[(x + 3)2/3]3 = 13(x + 3)2 = 1x2 + 6x + 9 = 1x2 + 6x + 8 = 0(x + 4)(x + 2) = 0x + 4 = 0 or x + 2 = 0x = -4 or x = -2Both solutions do check. The solution set is {-4, -2}. solve each equation. [2x - 4]2/3 = 1
The following equations are also quadratic in form. To solve, begin by raising each side of the equation to the appropriate power so that the exponent will become an integer. Then, to solve the resulting quadratic equation, you may use the square-root property, factoring, or the quadratic formula—whichever is most appropriate. Be aware that raising each side of the equation to a power may introduce extraneous roots; therefore, be sure to check your solutions. Study the following example before you begin the problems.Solve(x + 3)2/3 = 1[(x + 3)2/3]3 = 13(x + 3)2 = 1x2 + 6x + 9 = 1x2 + 6x + 8 = 0(x + 4)(x + 2) = 0x + 4 = 0 or x + 2 = 0x = -4 or x = -2Both solutions do check. The solution set is {-4, -2}. solve each equation. [2x - 4]2/3 = 1
The following equations are also quadratic in form. To solve, begin by raising each side of the equation to the appropriate power so that the exponent will become an integer. Then, to solve the resulting quadratic equation, you may use the square-root property, factoring, or the quadratic formula—whichever is most appropriate. Be aware that raising each side of the equation to a power may introduce extraneous roots; therefore, be sure to check your solutions. Study the following example before you begin the problems. Solve (x + 3)2/3 = 1 [(x + 3)2/3]3 = 13 (x + 3)2 = 1 x2 + 6x + 9 = 1 x2 + 6x + 8 = 0 (x + 4)(x + 2) = 0 x + 4 = 0 or x + 2 = 0 x = -4 or x = -2 Both solutions do check. The solution set is {-4, -2}. solve each equation. [2x - 4]2/3 = 1
Formula Formula A polynomial with degree 2 is called a quadratic polynomial. A quadratic equation can be simplified to the standard form: ax² + bx + c = 0 Where, a ≠ 0. A, b, c are coefficients. c is also called "constant". 'x' is the unknown quantity
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