The following equation represents the -partial combustion of methane, CH4 2CH4(g) + 302(g) → 2C0(g) + 4H2O(g); At constant temperature and pressure, what is the maximum volume of carbon monoxide that can be obtained from 6.62 x 102 L of methane and ?3.31 x 102 L of oxygen L 102 x 2.21 .a O L 102 x 9.93 .b O L 103 x 1.32.c O L 102 x 6.62 .d O L 103 x 2.32.e o

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Chapter5: Gases
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The following equation represents the
.partial combustion of methane, CH4
2CH4(g) + 302(g) 2C0(g) + 4H2O(g);
At constant temperature and pressure,
what is the maximum volume of carbon
monoxide that can be obtained from
6.62 x 102 L of methane and
?3.31 x 102 L of oxygen
L 102 x 2.21 .a O
L 102 x 9.93 .b O
L 103 x 1.32.C O
L 102 x 6.62 .d O
L 10° x 2.32.e O
الصفحة التالية
Transcribed Image Text:The following equation represents the .partial combustion of methane, CH4 2CH4(g) + 302(g) 2C0(g) + 4H2O(g); At constant temperature and pressure, what is the maximum volume of carbon monoxide that can be obtained from 6.62 x 102 L of methane and ?3.31 x 102 L of oxygen L 102 x 2.21 .a O L 102 x 9.93 .b O L 103 x 1.32.C O L 102 x 6.62 .d O L 10° x 2.32.e O الصفحة التالية
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