The following drive system is used to raise a load at constant velocity. The motor rotational speed is 1000 rpm, and the rotational speed of the drum is 200 rpm. The efficiency of the gear box is 0.85. The efficiency of the drum is 0.95%. The moment of inertia of the motor (input shaft) is 0.5 kg.m², and the moment of inertia of the drum (output shaft) is 0.75 kg.m². Calculate: (1) The total (equivalent) moment of inertia of the drive system referred to the motor shaft. (2) The developed mechanical power on the motor Drum, 0.5 m diameter shaft. 1000 Kg Motor Gearbox

The following drive system is used to raise a load at constant velocity. The motor rotational speed is 1000 rpm, and the rotational speed of the drum is 200 rpm. The efficiency of the gear box is 0.85. The efficiency of the drum is 0.95%. The moment of inertia of the motor (input shaft) is 0.5 kg.m², and the moment of inertia of the drum (output shaft) is 0.75 kg.m². Calculate: (1) The total (equivalent) moment of inertia of the drive system referred to the motor shaft. (2) The developed mechanical power on the motor Drum, 0.5 m diameter shaft. 1000 Kg Motor Gearbox

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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