The following data represent the weekly salary of 10 people. Complete parts (a) through (e) below. 260 370 670 860 990 260 260 370 370 260 Question content area bottom Part 1 a. Obtain the sample mean and sample standard deviation of the (ungrouped) data set. x=enter your response here Part 2 sx=enter your response here (Round to one decimal place as needed.) Part 3 b. A frequency distribution for the data, using single-value grouping, is presented in the first two columns of the following table. The third column of the table is for the xf-values. Complete the missing entries in the table and then use the grouped-data formula to obtain the sample mean. Salary x Frequency f Salary•Frequency xf 260 4 1,040 370 3 enter your response here 670 1 enter your response here 860 1 enter your response here 990 1 enter your response here Part 4 Obtain the sample mean. x=enter your response here Part 5 c. Explain why the grouped-data formula always yields the actual sample mean when the data are grouped by using single-value grouping. A. The sum of the xf values Σxi•fi for the grouped-data is equal to the actual mean (x). B. The sum of the xf values Σxi•fi for the grouped-data is equal to the sum of data (Σxi) for the non grouped-data. C. The sum of the xf values Σxi•fi for the grouped-data is equal to the actual standard deviation (sx). D. The sample means are not the same. Part 6 d. Complete the table, then use the table and the grouped-data formula to obtain the sample standard deviation. Salary x Frequency f Deviation from mean x−x Squared deviation x−x2 Squared deviation•Frequency x−x2•f 260 4 enter your response here enter your response here enter your response here 370 3 enter your response here enter your response here enter your response here 670 1 enter your response here enter your response here enter your response here
The following data represent the weekly salary of 10 people. Complete parts (a) through (e) below. 260 370 670 860 990 260 260 370 370 260 Question content area bottom Part 1 a. Obtain the sample mean and sample standard deviation of the (ungrouped) data set. x=enter your response here Part 2 sx=enter your response here (Round to one decimal place as needed.) Part 3 b. A frequency distribution for the data, using single-value grouping, is presented in the first two columns of the following table. The third column of the table is for the xf-values. Complete the missing entries in the table and then use the grouped-data formula to obtain the sample mean. Salary x Frequency f Salary•Frequency xf 260 4 1,040 370 3 enter your response here 670 1 enter your response here 860 1 enter your response here 990 1 enter your response here Part 4 Obtain the sample mean. x=enter your response here Part 5 c. Explain why the grouped-data formula always yields the actual sample mean when the data are grouped by using single-value grouping. A. The sum of the xf values Σxi•fi for the grouped-data is equal to the actual mean (x). B. The sum of the xf values Σxi•fi for the grouped-data is equal to the sum of data (Σxi) for the non grouped-data. C. The sum of the xf values Σxi•fi for the grouped-data is equal to the actual standard deviation (sx). D. The sample means are not the same. Part 6 d. Complete the table, then use the table and the grouped-data formula to obtain the sample standard deviation. Salary x Frequency f Deviation from mean x−x Squared deviation x−x2 Squared deviation•Frequency x−x2•f 260 4 enter your response here enter your response here enter your response here 370 3 enter your response here enter your response here enter your response here 670 1 enter your response here enter your response here enter your response here
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
The following data represent the weekly salary of 10 people. Complete parts (a) through (e) below.
260
|
370
|
670
|
860
|
990
|
|
260
|
260
|
370
|
370
|
260
|
|
Question content area bottom
Part 1
a. Obtain the sample mean and sample standard deviation of the (ungrouped) data set.
x=enter your response here
Part 2
sx=enter your response here
(Round to one decimal place as needed.)Part 3
b. A frequency distribution for the data, using single-value grouping, is presented in the first two columns of the following table. The third column of the table is for the xf-values. Complete the missing entries in the table and then use the grouped-data formula to obtain the sample mean.
Salary
x
|
Frequency
f
|
Salary•Frequency
xf
|
---|---|---|
260
|
4
|
1,040
|
370
|
3
|
enter your response here
|
670
|
1
|
enter your response here
|
860
|
1
|
enter your response here
|
990
|
1
|
enter your response here
|
Part 4
Obtain the sample mean.
x=enter your response here
Part 5
c. Explain why the grouped-data formula always yields the actual sample mean when the data are grouped by using single-value grouping.
The sum of the xf values
Σxi•fi
for the grouped-data is equal to the actual mean
(x).
The sum of the xf values
Σxi•fi
for the grouped-data is equal to the sum of data
(Σxi)
for the non grouped-data.The sum of the xf values
Σxi•fi
for the grouped-data is equal to the actual standard deviation
(sx).
The sample means are not the same.
Part 6
d. Complete the table, then use the table and the grouped-data formula to obtain the sample standard deviation.
Salary
x
|
Frequency
f
|
Deviation from mean
x−x
|
Squared deviation
x−x2
|
Squared deviation•Frequency
x−x2•f
|
---|---|---|---|---|
260
|
4
|
enter your response here
|
enter your response here
|
enter your response here
|
370
|
3
|
enter your response here
|
enter your response here
|
enter your response here
|
670
|
1
|
enter your response here
|
enter your response here
|
enter your response here
|
860
|
1
|
enter your response here
|
enter your response here
|
enter your response here
|
990
|
1
|
enter your response here
|
enter your response here
|
enter your response here
|
Part 7
sx=enter your response here
(Round to one decimal place as needed.)Part 8
e. Explain why the grouped-data formula always yields the actual sample standard deviation when the data are grouped by using single-value grouping.
The sum of the squared deviations times the frequency
Σxi−x2fi
for the group-data formula is equal to the sample mean of the data
(x).
The sum of the squared deviations times the frequency
Σxi−x2fi
for the group-data formula is equal to the sum of the squared deviations
Σxi−x2
for the non grouped-data.The sum of the squared deviations times the frequency
Σxi−x2fi
for the group-data formula is equal to the actual sample standard deviation
(sx).
The two sample standard deviations are different.
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