The following data is representative of that reported in the article "An Experimental Correlation of Oxides of Nitrogen Emissions from Power Boilers Based on Fleld Data,"t with x = burner-area liberation rate (MBtu/hr-ft?) and y = NO, emission rate (ppm). 100 125 125 150 150 200 200 250 250 300 300 350 400 400 150 140 180 210 190 320 280 400 430 440 390 600 610 670 The equation of the estimated regression line is y = -45.55190539 + 1.71143233x. [sSE (a) Obtain SSE for the data from the defining formula SSE = (Y, - (Round your answer to two decimal places.) Compare to the value calculated from the computational formula. (When comparing, round your value from the computational formula to two declmal places.) Rounded to two decimal places the value from the computational formula is --Select-- v the defining formula. (b) Calculate the value of total sum of squares. (Round your answer to two decimal places.) Does the simple linear regression model appear to do an effective job of explaining variation in emission rate? Justify your assertion. (Assume that a value of r2 greater than 0.85 is large enough to consider the model successful.) Since, rounded to two decimal places, r = , the simple linear regression model --Select-- to do an effective job of explaining varlatlon in emisslon rate.
The following data is representative of that reported in the article "An Experimental Correlation of Oxides of Nitrogen Emissions from Power Boilers Based on Fleld Data,"t with x = burner-area liberation rate (MBtu/hr-ft?) and y = NO, emission rate (ppm). 100 125 125 150 150 200 200 250 250 300 300 350 400 400 150 140 180 210 190 320 280 400 430 440 390 600 610 670 The equation of the estimated regression line is y = -45.55190539 + 1.71143233x. [sSE (a) Obtain SSE for the data from the defining formula SSE = (Y, - (Round your answer to two decimal places.) Compare to the value calculated from the computational formula. (When comparing, round your value from the computational formula to two declmal places.) Rounded to two decimal places the value from the computational formula is --Select-- v the defining formula. (b) Calculate the value of total sum of squares. (Round your answer to two decimal places.) Does the simple linear regression model appear to do an effective job of explaining variation in emission rate? Justify your assertion. (Assume that a value of r2 greater than 0.85 is large enough to consider the model successful.) Since, rounded to two decimal places, r = , the simple linear regression model --Select-- to do an effective job of explaining varlatlon in emisslon rate.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![The following data is representative of that reported in the article "An Experimental Correlation of Oxides of Nitrogen Emissions from Power Boilers Based on Field Data," with \( x = \) burner-area liberation rate (MBtu/hr-ft\(^2\)) and \( y = \) NO\(_x\) emission rate (ppm).
| \( x \) | 100 | 125 | 125 | 150 | 200 | 250 | 250 | 300 | 350 | 400 | 400 |
|--------|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|
| \( y \) | 150 | 140 | 180 | 210 | 190 | 320 | 280 | 430 | 440 | 690 | 610 | 670 |
The equation of the estimated regression line is \( y = -45.55190539 + 1.71143233x \).
(a) Obtain SSE for the data from the defining formula \( \text{SSE} = \sum (y_i - \hat{y}_i)^2 \). (Round your answer to two decimal places.)
[Text box for answer]
Compare to the value calculated from the computational formula. (When comparing, round your value from the computational formula to two decimal places.)
Rounded to two decimal places the value from the computational formula is [Dropdown] the defining formula.
(b) Calculate the value of total sum of squares. (Round your answer to two decimal places.)
[Text box for answer]
Does the simple linear regression model appear to do an effective job of explaining variation in emission rate? Justify your assertion. (Assume that a value of \( r^2 \) greater than 0.85 is large enough to consider the model successful.)
Since, rounded to two decimal places, \( r^2 = \) [Text box for answer], the simple linear regression model [Dropdown] to do an effective job of explaining variation in emission rate.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffea4cb18-f853-4dd5-87f1-44780e7d8dd9%2Fb17dfa05-0760-47eb-83f4-0afd6222087e%2Fi7geg9i_processed.png&w=3840&q=75)
Transcribed Image Text:The following data is representative of that reported in the article "An Experimental Correlation of Oxides of Nitrogen Emissions from Power Boilers Based on Field Data," with \( x = \) burner-area liberation rate (MBtu/hr-ft\(^2\)) and \( y = \) NO\(_x\) emission rate (ppm).
| \( x \) | 100 | 125 | 125 | 150 | 200 | 250 | 250 | 300 | 350 | 400 | 400 |
|--------|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|
| \( y \) | 150 | 140 | 180 | 210 | 190 | 320 | 280 | 430 | 440 | 690 | 610 | 670 |
The equation of the estimated regression line is \( y = -45.55190539 + 1.71143233x \).
(a) Obtain SSE for the data from the defining formula \( \text{SSE} = \sum (y_i - \hat{y}_i)^2 \). (Round your answer to two decimal places.)
[Text box for answer]
Compare to the value calculated from the computational formula. (When comparing, round your value from the computational formula to two decimal places.)
Rounded to two decimal places the value from the computational formula is [Dropdown] the defining formula.
(b) Calculate the value of total sum of squares. (Round your answer to two decimal places.)
[Text box for answer]
Does the simple linear regression model appear to do an effective job of explaining variation in emission rate? Justify your assertion. (Assume that a value of \( r^2 \) greater than 0.85 is large enough to consider the model successful.)
Since, rounded to two decimal places, \( r^2 = \) [Text box for answer], the simple linear regression model [Dropdown] to do an effective job of explaining variation in emission rate.
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