The following data are the distances between 26 retail stores and a large distribution center. The distances are in miles. 9 109, 123, 126, 147, 148, 153, 156, 156, 157, 164, 165, 169, 182, 189, 198, 198, 208, 211, 216, 226, 236, 242, 250, 259, 277 Find the sample mean of the data: miles Find the sample standard deviation of the data: S = miles Find any outliers in the data. If there are multiple outliers, separate them with a comma. If the data has no outliers, select "No Outliers." O Outliers: O No Outliers

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The following data are the distances between 26 retail stores and a large distribution center. The
distances are in miles.
9 109, 123, 126, 147, 148, 153, 156, 156, 157, 164, 165, 169, 182, 189, 198, 198, 208, 211, 216, 226,
236, 242, 250, 259, 277
Find the sample mean of the data:
miles
Find the sample standard deviation of the data:
S =
miles
Find any outliers in the data. If there are multiple outliers, separate them with a comma. If the data
has no outliers, select "No Outliers."
O Outliers:
O No Outliers
Transcribed Image Text:The following data are the distances between 26 retail stores and a large distribution center. The distances are in miles. 9 109, 123, 126, 147, 148, 153, 156, 156, 157, 164, 165, 169, 182, 189, 198, 198, 208, 211, 216, 226, 236, 242, 250, 259, 277 Find the sample mean of the data: miles Find the sample standard deviation of the data: S = miles Find any outliers in the data. If there are multiple outliers, separate them with a comma. If the data has no outliers, select "No Outliers." O Outliers: O No Outliers
Expert Solution
Step 1

Data represents the distances between 26 retail stores and a large distribution center . The distances are in miles . 

It's mean is computed as : 

x¯=i=1nxin=90+109+123+...+27726=475526=182.8846 

x¯ = 183 miles

It's standard deviation is computed as: 

s= i=1n(xi-x¯)2n-1=(90-182.8846)2+(109-182.8846)2+...+(277-182.8846)226-1                             s= 48.0144 miles  

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