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The following data are for the gas phase decomposition of dinitrogen pentoxide at 335 K. N₂O5(g) - 2 NO₂(g) + O₂(g)

The following data are for the gas phase decomposition of dinitrogen pentoxide at 335 K. N₂O5(g) - 2 NO₂(g) + O₂(g)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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cvg.cengagenow.com The following data are for the gas phase decomposition of dinitrogen pentoxide at 335 K. 2 NO₂(g) + 1/ 0₂(g) N₂05(g) - - [N₂O5 ], M time, s 0.199 0 S OWLV2 | Online teaching and learning resource from Cengage Learning 9.95x10-2 116 Hint: It is not necessary to graph these data. (1) The half life observed for this reaction is In progress (2) Based on these data, the rate constant for this 4.98x10-2 2.49x10-² 232 348 + 88 S. 99% order reaction is 2.
Transcribed Image Text:cvg.cengagenow.com The following data are for the gas phase decomposition of dinitrogen pentoxide at 335 K. 2 NO₂(g) + 1/ 0₂(g) N₂05(g) - - [N₂O5 ], M time, s 0.199 0 S OWLV2 | Online teaching and learning resource from Cengage Learning 9.95x10-2 116 Hint: It is not necessary to graph these data. (1) The half life observed for this reaction is In progress (2) Based on these data, the rate constant for this 4.98x10-2 2.49x10-² 232 348 + 88 S. 99% order reaction is 2.
Expert Solution
Step 1

1.

From the data given

 0-sec  concentration = 0.199 M

 after 122 sec, concentration = 0.199/2 = 0.0995 M

 it is half of the initial concentration. so that half-life time(T1/2)= 116 sec

1.  answer: 116 sec

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