The following algorithm takes as input two non-negative integers, x and y, and returns the product of x and y. FastMult (x, y) Input: Two non-negative integers, x and y Output: The product of x and y If (y 0), Return( 0 ) floor (y/2) //floor is the mathematical floor function := := FastMult (x, z) // The recursive call If (y is even) Return( 2 p ) Else Return( 2 p + x ) End-if Give a recurrence relation to describe the asymptotic complexity of the algorithm.

The following algorithm takes as input two non-negative integers, x and y, and returns the product of x and y. FastMult (x, y) Input: Two non-negative integers, x and y Output: The product of x and y If (y 0), Return( 0 ) floor (y/2) //floor is the mathematical floor function := := FastMult (x, z) // The recursive call If (y is even) Return( 2 p ) Else Return( 2 p + x ) End-if Give a recurrence relation to describe the asymptotic complexity of the algorithm.

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 1TF

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CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021
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