The following algorithm finds the same character in two strings: string, =X1X2X, and string, =yıy2".Yn: How many times would Step 4.1.1. be performed for the following inputs: string1 6632176980 string 2=8703125409 1. input n 2. input the n-character long string x1x2X3 * Xn 3. input the n-character long string y1y2y3 ** Yn 4. for i = 1 to n do 4.1. for j = 1 to n do 4.1.1. if x = y; then 4.1.1.1. return "A common character has been found; it is x;" 5. return "There is no common character in the given two strings"
The following algorithm finds the same character in two strings: string, =X1X2X, and string, =yıy2".Yn: How many times would Step 4.1.1. be performed for the following inputs: string1 6632176980 string 2=8703125409 1. input n 2. input the n-character long string x1x2X3 * Xn 3. input the n-character long string y1y2y3 ** Yn 4. for i = 1 to n do 4.1. for j = 1 to n do 4.1.1. if x = y; then 4.1.1.1. return "A common character has been found; it is x;" 5. return "There is no common character in the given two strings"
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:QUESTION7
The following algorithm finds the same character in two strings: string, =X1X2X, and string, =yıy2".Yn: How many times would Step
4.1.1. be performed for the following inputs:
string1=6632176980
string 2=8703125409
1. input n
2. input the n-character long string x1X2X3 Xn
3. input the n-character long string y1y2Y3 * Yn
4. for i = 1 to n do
4.1. for j = 1 to n do
4.1.1. if x; = y; then
4.1.1.1. return "A common character has been found; it is x;"
5. return "There is no common character in the given two strings"
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