Find the current ic(t) at the steady-state for R = 49, C = F, L = 2H, 16 v₂ (t) = 5 cos(4t + 60°) V and i, (t) = 2 sin(2t - 30°)A.
Find the current ic(t) at the steady-state for R = 49, C = F, L = 2H, 16 v₂ (t) = 5 cos(4t + 60°) V and i, (t) = 2 sin(2t - 30°)A.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question
![Find the current ic(t) at the steady-state for R = 49, C
v₂ (t) = 5 cos(4t + 60°) V and i, (t) = 2 sin(2t - 30°)A.
L vic(t)
Js(t)
R
C
is(t)
= -F, L =
16
2H,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F25b98205-ee11-4340-b2c6-069b84298498%2Fbcc3de80-7eb9-44cf-9f2f-1b31acc3a515%2Fps5065d_processed.png&w=3840&q=75)
Transcribed Image Text:Find the current ic(t) at the steady-state for R = 49, C
v₂ (t) = 5 cos(4t + 60°) V and i, (t) = 2 sin(2t - 30°)A.
L vic(t)
Js(t)
R
C
is(t)
= -F, L =
16
2H,
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Follow-up Questions
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Follow-up Question
the follow up question wasnt answered properly the question wasnt about the superposition theorm it was about ic1=5<60 /.... and ic2=4+j4 .... can you please explain how you got both formulas in detail? thank you.
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Follow-up Question
everything is good and the answer is correct but what i didnt understand is how did u find the relation between ic1 and ic2 how did u get to that formula? can you please explain that in more depth? please do not just state the law but explain in detail. Thank you!
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