The flux through this Gaussian surface is?
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A point charge +Q is located on the x-axis at x = a, and a second point charge -3Q is located on the x axis at x = -a. A cubic Gaussian surface with sides l = 4a is centered at the origin. The flux through this Gaussian surface is?

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- A point charge is located at the center of two thin, concentric, non-conducting spherical shells (both uniformly charged). The flux through a gaussian sphere of different radii (centered at point P) is as follows: = 1.6 x 106 Nm²/C (for r r₂). What is the charge at point P? qp = What is the charge on shell 2? 92² C. Recall that 1 μC = 106 C. μC. 12. P 2A charged particle is held at the center of two concentric conducting spherical shells. Figure (a) shows a cross-section. Figure (b) gives the net flux & through a Gaussian sphere centered on the particle, as a function of the radius r of the sphere. The scale of the vertical axis is set by o, = 5.0×10° N.m/C. What are (a) the charge of the central particle and the net charges of (b) shell A Q3. and (c) shell B? (a) (B) (10°N• m/C)A charge is initially surrounded by a cubic Gaussian surface whose volume is d³. The cubic surface is replaced by a spherical surface of radius d/2. The net flux of the spherical surface is none of the above. equal to the net flux through the cube. greater than the net flux through the cube. less than the net flux through the cube.
- A charged particle is located at the center of two concentric conducting spherical shells, as shown below. The inner shell (in blue) has inner and outer radii a and b; the outer shell (in green) has radii c and d. Both shells may also carry a net charge. The plot shows the electric flux of a Gaussian spherical surface centered on the particle as a function of the radius r. Using Gauss’s law and the plot, find expressions for the following (in terms of Φ0): (a) The charge of the particle in the center (b) The net charge on the blue conducting shell (c) The net charge on the green conducting shellWe place a point charge q at the center of a sphere of radius R. This results in an electric field E at the surface of the sphere and a flux 4 passing through it. If we change the radius of the sphere to R' = 2R, what happens to the electric field E' at the surface and the flux ' passing through this new sphere? Surface area A = 4πR², Volume V = =πR³.Please Asap
- A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a circle of radius R (see the figure). The central perpendicular axis through the ring is a z axis, with the origin at the center of the ring. What is the magnitude of the electric field due to the rod at (a) z = 0 and (b) z = ∞? (c) In terms of R, at what positive value of z is that magnitude maximum? (d) If R = 2.07 cm and Q = 4.25 μC, what is the maximum magnitude? (a) Number C R i (b) Number i (c) Number i (d) Number i Units N/C Units N/ Units No units Units N/OA hollow sphere of radui R has a uniform nagative surface charge density -\sigma on its surface and a positive point charge +Q at its center. The charge Q is greater than the absolute magnitude of the total charge on the surface. The direction of the E-field is radially outward both inside and outside the sphere. What is the magnitude of the E-field inside the sphere at a distance r<R from the center? What is the magnitude of the E-field outside the sphere at a distance r<R from the center?