The flooring of a warehouse is made up of double - tee oints. The joints are simply-supported on a span of 8 m are pre-tensioned with one tendon in each stem with ar nitial jacking force of 750 kN each, located 75 mm abov he bottom fiber, loss of prestress at service loads is 20 X

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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The flooring of a warehouse is made up of double - tee
joints. The joints are simply-supported on a span of 8 m and
are pre-tensioned with one tendon in each stem with an
initial jacking force of 750 kN each, located 75 mm above
the bottom fiber, loss of prestress at service loads is 20%.
-NA.
Y2
Уз
P = 750 kN each
A = 220,000 mm?
13 1890 x 106 тm*
Yı = 90 mm
Уг 3D 270 тт
Y3 = 75 mm
simple span, L = 8 m
x = 2.5 m
Ye = 23.5 kN.
m3
1. Determine the initial stress at the bottom fibers due to prestressing force alone.
2. Determine the stress at the bottom fiber due to service load and prestressing force.
Assume that there is a loss of prestress of 20% at service loads.
Service Loads:
DL = 2.5 kPa
LL = 6 kPa
3. Calculate the additional load the floor can carry so that the stress at the bottom
fibers at the midspan is zero.
Transcribed Image Text:The flooring of a warehouse is made up of double - tee joints. The joints are simply-supported on a span of 8 m and are pre-tensioned with one tendon in each stem with an initial jacking force of 750 kN each, located 75 mm above the bottom fiber, loss of prestress at service loads is 20%. -NA. Y2 Уз P = 750 kN each A = 220,000 mm? 13 1890 x 106 тm* Yı = 90 mm Уг 3D 270 тт Y3 = 75 mm simple span, L = 8 m x = 2.5 m Ye = 23.5 kN. m3 1. Determine the initial stress at the bottom fibers due to prestressing force alone. 2. Determine the stress at the bottom fiber due to service load and prestressing force. Assume that there is a loss of prestress of 20% at service loads. Service Loads: DL = 2.5 kPa LL = 6 kPa 3. Calculate the additional load the floor can carry so that the stress at the bottom fibers at the midspan is zero.
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