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The floor system shown is made of concrete (self-weight of concrete is 25kN/m³). Its thickness is t. The slab is supported on beams on all sides on its perimeter. Find: (a) The weight of the slab as uniformly distributed load per unit area of slab (in kN/m²) (b) the distributed load that is transferred to the beams using proper tributary areas (in kN/m) D is the last digit of your student number = ... 2 6*Z t= 0.30m+0.05*D (in meters) = 0.4m Z = 5m + 0.1*D (in meters) = 5.2 m %3D

The floor system shown is made of concrete (self-weight of concrete is 25kN/m³). Its thickness is t. The slab is supported on beams on all sides on its perimeter. Find: (a) The weight of the slab as uniformly distributed load per unit area of slab (in kN/m²) (b) the distributed load that is transferred to the beams using proper tributary areas (in kN/m) D is the last digit of your student number = ... 2 6*Z t= 0.30m+0.05*D (in meters) = 0.4m Z = 5m + 0.1*D (in meters) = 5.2 m %3D

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Problem 2: The floor system shown is made of concrete (self-weight of concrete is 25KN/m³). Its thickness is t. The slab is supported on beams on all sides on its perimeter. Find: (a) The weight of the slab as uniformly distributed load per unit area of slab (in kN/m²) (b) the distributed load that is transferred to the beams using proper tributary areas (in kN/m) D is the last digit of your student number = ... 2 0.6*Z t= 0.30m+0.05*D (in meters) = 0.4m Z = 5m + 0.1*D (in meters) = 5.2 m %3D %3D
Transcribed Image Text:Problem 2: The floor system shown is made of concrete (self-weight of concrete is 25KN/m³). Its thickness is t. The slab is supported on beams on all sides on its perimeter. Find: (a) The weight of the slab as uniformly distributed load per unit area of slab (in kN/m²) (b) the distributed load that is transferred to the beams using proper tributary areas (in kN/m) D is the last digit of your student number = ... 2 0.6*Z t= 0.30m+0.05*D (in meters) = 0.4m Z = 5m + 0.1*D (in meters) = 5.2 m %3D %3D
Expert Solution
Step 1

Given Data

Floor system made of concrete

Self weight of concrete = 25 kN/m3

D=2

Thickness of slab = t = 0.25m+0.05*D (m) = 0.35 m

(a) Weight of the slab as uniformly distributed load per unit area of slab = Weight of concrete per m3 * Thickness of slab

= 25 (kN/m3) *0.35 (m) = 8.75 kN/m2

 

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