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The floor of an apartment building is subjected to a uniformly distributed load of 45 psf over its surface area. Determine the point load at B on girder AC. Floor beam A FH- B G L a. 90,000 lb b. 45,000 lb c. 11,250 lb d. 22,500 lb H M 4 at 25 ft 100 ft- D N Girder E 0 Column 2 at 40 ft = 80 ft

The floor of an apartment building is subjected to a uniformly distributed load of 45 psf over its surface area. Determine the point load at B on girder AC. Floor beam A FH- B G L a. 90,000 lb b. 45,000 lb c. 11,250 lb d. 22,500 lb H M 4 at 25 ft 100 ft- D N Girder E 0 Column 2 at 40 ft = 80 ft

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The floor of an apartment building is subjected to a uniformly distributed load of 45 psf over its surface area. Determine the point load at B on girder AC. 

**Problem Description:** The floor of an apartment building is subjected to a uniformly distributed load of 45 psf over its surface area. Determine the point load at B on girder AC. **Diagram Explanation:** The diagram depicts a structural grid for the floor of an apartment building, consisting of floor beams, girders, and columns. The diagram includes the following key elements: 1. **Nodes and Members:** - The joints (nodes) between structural members are labeled with letters (A, B, C, etc.). - Horizontal members connected between node pairs (e.g., AC, DF) represent the girders. - Vertical members such as AD, DF are the columns or supporting structures. 2. **Dimensions:** - The horizontal span between nodes (AB, BC, CD, etc.) is 25 ft, making the total length of AC 100 ft (4 spans of 25 ft each). - The vertical span between nodes (JF, GF, HF, etc.) is labeled as 40 ft, with a total vertical height shown as 80 ft (2 spans of 40 ft each). 3. **Loads:** - The load distribution is uniformly specified as 45 psf (pounds per square foot) over the entire floor area. **Calculation Explanation:** To determine the point load at B on the girder AC, given the uniformly distributed load of 45 psf: 1. **Floor Area:** - Total floor area under consideration = 100 ft (length) x 80 ft (width) = 8,000 sq ft. 2. **Total uniform load:** - Total load applied = Area x Load per unit area = 8,000 sq ft x 45 psf = 360,000 lbs. 3. **Determining Point Load at B:** - Considering symmetry and uniform load distribution; - Girder AC is symmetrically loaded. It supports the load via columns at points A, B, C, D, and E. 4. **Point Load Calculation:** - At each node (A, B, C, D, E), assuming equal load distribution: - Total load distributed equally among the 5 points (i.e., A, B, C, D, and E) on the girder = 360,000 lbs / 8 = 45,000 lbs (assuming only external columns resist
Transcribed Image Text:**Problem Description:** The floor of an apartment building is subjected to a uniformly distributed load of 45 psf over its surface area. Determine the point load at B on girder AC. **Diagram Explanation:** The diagram depicts a structural grid for the floor of an apartment building, consisting of floor beams, girders, and columns. The diagram includes the following key elements: 1. **Nodes and Members:** - The joints (nodes) between structural members are labeled with letters (A, B, C, etc.). - Horizontal members connected between node pairs (e.g., AC, DF) represent the girders. - Vertical members such as AD, DF are the columns or supporting structures. 2. **Dimensions:** - The horizontal span between nodes (AB, BC, CD, etc.) is 25 ft, making the total length of AC 100 ft (4 spans of 25 ft each). - The vertical span between nodes (JF, GF, HF, etc.) is labeled as 40 ft, with a total vertical height shown as 80 ft (2 spans of 40 ft each). 3. **Loads:** - The load distribution is uniformly specified as 45 psf (pounds per square foot) over the entire floor area. **Calculation Explanation:** To determine the point load at B on the girder AC, given the uniformly distributed load of 45 psf: 1. **Floor Area:** - Total floor area under consideration = 100 ft (length) x 80 ft (width) = 8,000 sq ft. 2. **Total uniform load:** - Total load applied = Area x Load per unit area = 8,000 sq ft x 45 psf = 360,000 lbs. 3. **Determining Point Load at B:** - Considering symmetry and uniform load distribution; - Girder AC is symmetrically loaded. It supports the load via columns at points A, B, C, D, and E. 4. **Point Load Calculation:** - At each node (A, B, C, D, E), assuming equal load distribution: - Total load distributed equally among the 5 points (i.e., A, B, C, D, and E) on the girder = 360,000 lbs / 8 = 45,000 lbs (assuming only external columns resist
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