The flanged steel cantilever beam with riveted bracket is subjected to the couple and two forces shown, and their effect on the design of the attachment at A must be determined. Replace the two forces and couple by an equivalent couple M and resultant R at A. The couple is positive if counterclockwise, negative if clockwise. A Answers: 1.24 m- 440 N-m 0.44 m 1.86 KN 72⁰ 10.18 m 0.18 m 1.17 KN
The flanged steel cantilever beam with riveted bracket is subjected to the couple and two forces shown, and their effect on the design of the attachment at A must be determined. Replace the two forces and couple by an equivalent couple M and resultant R at A. The couple is positive if counterclockwise, negative if clockwise. A Answers: 1.24 m- 440 N-m 0.44 m 1.86 KN 72⁰ 10.18 m 0.18 m 1.17 KN
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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P1a please help me with the answer and full solution
![The
flanged steel cantilever beam with riveted bracket is subjected to the couple and two forces shown, and their effect on the design
of the attachment at A must be determined. Replace the two forces and couple by an equivalent couple M and resultant R at A. The
couple is positive if counterclockwise, negative if clockwise.
A
Answers:
M = i
R = (i
1.24 m-
440 Nm
0.44 m
kN.m
i+i
1.86 KN
72°
0.18 m
0.18 m
1.17 KN
j) KN](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc080f015-0308-4b54-980e-2fe7fccc7ef0%2Fd5434e83-238f-44fb-a4aa-f40fe7dd2460%2Fg0pgxah_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The
flanged steel cantilever beam with riveted bracket is subjected to the couple and two forces shown, and their effect on the design
of the attachment at A must be determined. Replace the two forces and couple by an equivalent couple M and resultant R at A. The
couple is positive if counterclockwise, negative if clockwise.
A
Answers:
M = i
R = (i
1.24 m-
440 Nm
0.44 m
kN.m
i+i
1.86 KN
72°
0.18 m
0.18 m
1.17 KN
j) KN
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