The first photo I provided an example of how my professor wants us to do it. It's confusing for me this is why I'm asking for help, thank you in advance :) Theorem 2.4.1The sum of the measures of the interrorangles of aA AB CProve: mcA+mcBtmk1 180triangle is 18o°.Given:T.A1. Given2 Paralled postulate : througha line there exists a unique line|to gren line3. for l lanes, alt. int. 2s are a ;21. AABC2. CB Il ABpoint noton3 2B 2 DCBZA LECAmeB= MLDCB, meA=m LECA5.LECB, LDCB are Suppl.4. Ls have = mias;5. adj. Ls w. ext. sides opp, rays4.6. m LECB t m LD CB =1807 m LECB3M LECAT melaresuppl; pret.6. Sum of meen. of uppl. s is80;5mees.1. Angle add. pests pict8. MCECA + mU + m LDCB = 1809.8. Sube titution, Gi?9. substitation;4,8+ m2i tmLB =180eop.LD CW 19 - 3/11Civen: AD IDC, BC LDClove: AD l BC2.3#19

Answered: Image /qna-images/answer/3cb317a3-85b4-40b4-bd9d-ad62c6a725b6.jpg

Answered: The first photo I provided an example…

The first photo I provided an example of how my professor wants us to do it. It's confusing for me this is why I'm asking for help, thank you in advance

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

ChapterP: Preliminary Concepts

SectionP.CT: Test

Problem 1CT

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Question

The first photo I provided an example of how my professor wants us to do it. It's confusing for me this is why I'm asking for help, thank you in advance :)

Theorem 2.4.1
The sum of the measures of the interror
angles of a
A AB C
Prove: mcA+mcBtmk1 180
triangle is 18o°.
Given:
T.
A
1. Given
2 Paralled postulate : through
a line there exists a unique line
|to gren line
3. for l lanes, alt. int. 2s are a ;2
1. AABC
2. CB Il AB
point not
on
3 2B 2 DCB
ZA LECA
meB= MLDCB, meA=m LECA
5.
LECB, LDCB are Suppl.
4. Ls have = mias;
5. adj. Ls w. ext. sides opp, rays
4.
6. m LECB t m LD CB =180
7 m LECB3M LECAT mel
aresuppl; pret.
6. Sum of meen. of uppl. s is
80;5
mees.
1. Angle add. pests pict
8. MCECA + mU + m LDCB = 180
9.
8. Sube titution, Gi?
9. substitation;4,8
+ m2i tmLB =180
eop.
LD

CW 19 - 3/11
Civen: AD IDC, BC LDC
love: AD l BC
2.3
#19

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