the first outcome is one of X and Y the second outcome is one of A and B if the first outcome is X, and one of A, B, and C if the first outcome is Y. Pr[X]=0.4Pr[X]=0.4Pr[Y]=0.6Pr[Y]=0.6Pr[A|X]=0.5Pr[A|X]=0.5Pr[B|X]=0.5Pr[B|X]=0.5Pr[A|Y]=0.3Pr[A|Y]=0.3Pr[B|Y]=0.2Pr[B|Y]=0.2Pr[C|Y]=0.5 (1) Pr[A]= (2) Pr[X|A]=Pr[X|A]= (3) Pr[Y|B]= (4) Pr[B|Y]=
the first outcome is one of X and Y the second outcome is one of A and B if the first outcome is X, and one of A, B, and C if the first outcome is Y. Pr[X]=0.4Pr[X]=0.4Pr[Y]=0.6Pr[Y]=0.6Pr[A|X]=0.5Pr[A|X]=0.5Pr[B|X]=0.5Pr[B|X]=0.5Pr[A|Y]=0.3Pr[A|Y]=0.3Pr[B|Y]=0.2Pr[B|Y]=0.2Pr[C|Y]=0.5 (1) Pr[A]= (2) Pr[X|A]=Pr[X|A]= (3) Pr[Y|B]= (4) Pr[B|Y]=
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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the first outcome is one of X and Y the second outcome is one of A and B if the first outcome is X, and one of A, B, and C if the first outcome is Y.
Pr[X]=0.4Pr[X]=0.4
Pr[Y]=0.6Pr[Y]=0.6
Pr[A|X]=0.5Pr[A|X]=0.5
Pr[B|X]=0.5Pr[B|X]=0.5
Pr[A|Y]=0.3Pr[A|Y]=0.3
Pr[B|Y]=0.2Pr[B|Y]=0.2
Pr[C|Y]=0.5
(1) Pr[A]=
(2) Pr[X|A]=Pr[X|A]=
(3) Pr[Y|B]=
(4) Pr[B|Y]=
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