The first-order rate constant for the thermal decomposition of 3-methylcyclobutanone has the values T/K k/1045-1 T/K k/104s-1 552.24 0.4259 589.05 6.459 561.81 0.8936 596.96 11.201 570.41 1.707 606.14 20.83 579.35 3.207 a. Find the value of the activation energy and the value of the preexponential factor. b. Find the value of the rate constant at 600.0 K. c. Find the time for 80.0% of the reactant to react at 600.0 K.
The first-order rate constant for the thermal decomposition of 3-methylcyclobutanone has the values T/K k/1045-1 T/K k/104s-1 552.24 0.4259 589.05 6.459 561.81 0.8936 596.96 11.201 570.41 1.707 606.14 20.83 579.35 3.207 a. Find the value of the activation energy and the value of the preexponential factor. b. Find the value of the rate constant at 600.0 K. c. Find the time for 80.0% of the reactant to react at 600.0 K.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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![The first-order rate constant for the thermal
decomposition of 3-methylcyclobutanone has the values
T/K k/1045-! T/K k/104s!
552.24 0.4259
589.05 6.459
561.81 0.8936
596.96 11.201
570.41 1.707
606.14 20.83
579.35 3.207
a. Find the value of the activation energy and the value
of the preexponential factor.
b. Find the value of the rate constant at 600.0 K.
c. Find the time for 80.0% of the reactant to react at
600.0 K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F62c9f99c-e7f8-4ae9-b4c3-4fa4157f646a%2Fc86b92ac-469f-4b4b-b5a5-2ac4ec8890e6%2F8moiy3j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The first-order rate constant for the thermal
decomposition of 3-methylcyclobutanone has the values
T/K k/1045-! T/K k/104s!
552.24 0.4259
589.05 6.459
561.81 0.8936
596.96 11.201
570.41 1.707
606.14 20.83
579.35 3.207
a. Find the value of the activation energy and the value
of the preexponential factor.
b. Find the value of the rate constant at 600.0 K.
c. Find the time for 80.0% of the reactant to react at
600.0 K.
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