The first-order rate constant for the conversion of cyclobutane to ethylene at 1000.°C is 101 s²¹. C₂H82 C₂H4 A. What is the half-life of the reaction at 1000."C? B. If you started with 3.350 g of cyclobutane, how long would it take to consume 0.4020 g of it? C. How much of a 2.50 g sample of cyclobutane would remain after 0.03430 s?

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7.
DETAILS
The first-order rate constant for the conversion of cyclobutane to ethylene at 1000.°C is 101 s ¹.
C4H8 → 2 C₂H4
A. What is the half-life of the reaction at 1000."C? [
B. If you started with 3.350 g of cyclobutane, how long would it take to consume 0.4020 g of it?
C. How much of a 2.50 g sample of cyclobutane would remain after 0.03430 s?
Useful Information:
1.013 bar = 760 torr = 1 atm = 760 mm Hg
h = 6.62607x10-34 3.s
c = 2.99792 x 108 m/s
R = 8.314472 3/mol.K
NA = 6.02214 x 1023 1/mol
R = 0.08205746 L.atm/mol.K
F = 9.648534 x 104 c/mol
Equations:
K= K (RT)An
AG=AHⓇ - TASⓇ
MY NOTES
pH = pk +log.
E = E
[A]
[HA]
7=45
0.05916
n
ASK YOUR TEACHER PRACTICE ANOTHER
log Qrxn
AG=-RTINK
AG=-nFE
1
[A]t
In(2)
k
[A] = [A]okt
1
=kt +
[A]
9
[A]
t=
k[A]
[A]
2k
-kt
-Ea
k Ae RT
Transcribed Image Text:7. DETAILS The first-order rate constant for the conversion of cyclobutane to ethylene at 1000.°C is 101 s ¹. C4H8 → 2 C₂H4 A. What is the half-life of the reaction at 1000."C? [ B. If you started with 3.350 g of cyclobutane, how long would it take to consume 0.4020 g of it? C. How much of a 2.50 g sample of cyclobutane would remain after 0.03430 s? Useful Information: 1.013 bar = 760 torr = 1 atm = 760 mm Hg h = 6.62607x10-34 3.s c = 2.99792 x 108 m/s R = 8.314472 3/mol.K NA = 6.02214 x 1023 1/mol R = 0.08205746 L.atm/mol.K F = 9.648534 x 104 c/mol Equations: K= K (RT)An AG=AHⓇ - TASⓇ MY NOTES pH = pk +log. E = E [A] [HA] 7=45 0.05916 n ASK YOUR TEACHER PRACTICE ANOTHER log Qrxn AG=-RTINK AG=-nFE 1 [A]t In(2) k [A] = [A]okt 1 =kt + [A] 9 [A] t= k[A] [A] 2k -kt -Ea k Ae RT
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