The financial department of the company that produces digital cameras arrived at the following price-demand function and the corresponding revenue function: p(x) = 94.8 – 5x R(x) = xp(x) = x(94.8 - 5x) – Price-demand function Revenue function where p(x)is the wholesale price per camera at which x million cameras can be sold and R(x) is the corresponding revenue (in millions of dollars). Both functions have domain 1 ≤ x ≤ 15. (a) Find the value of x to the nearest thousand cameras that will generate the maximum revenue. What is the maximum revenue to the nearest thousand dollars? Solve the problem algebraically by completing the square (b) What is the wholesale price per camera (to the nearest dollar) that generates the maximum revenue?