The final conclusion isO A. We can reject the null hypothesis that p = 0.65 and accept that p < 0.65.B. There is not sufficient evidence to reject the null hypothesis that p = 0.65.(3) Test Ho : p = 0.65 against H. : p + 0.65. Use a = 0.01.test statistic zpositive critical z scorenegative critical z scoreThe final conclusion isA. There is not sufficient evidence to reject the null hypothesis that pB. We can reject the null hypothesis that p = 0.65 and accept that p + 0.65.0.65. A random sample of 130 observations is selected from a binomial population with unknown probability ofThe computed value of p is 0.75.successр.(1) Test Ho : p = 0.55 against H. :p > 0.55. Use a = 0.05.%3Dtest statistic z =critical z scoreThe final conclusion isA. There is not sufficient evidence to reject the null hypothesis that p = 0.55.B. We can reject the null hypothesis that p = 0.55 and accept that p > 0.55.(2) Test Ho : p = 0.65 against Ha : p < 0.65. Use a0.01.%3Dtest statistic z =critical z scoreThe final conclusion isO A. We can reject the null hypothesis that p = 0.65 and accept that p < 0.65.B. There is not sufficient evidence to reject the null hypothesis that p = 0.65.(3) Test Ho : p = 0.65 against H. :p+0.65. Use a = 0.01.

Answered: The final conclusion is A. There is not…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Molly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She obtains a random sample of 120 containers of ground beef and finds that 84 percent have the correct fat content. Molly then conducts a hypothesis test of H0:p=0.80H0:p=0.80 versus Ha:p≠0.80Ha:p≠0.80 and calculates a test statistic of 1.10 with a pp-value of 0.273. Which of the following best represents the meaning of the pp-value? If the population proportion is 0.84, the probability of observing a sample proportion of 0.80 is 0.273. A If the population proportion is 0.84, the probability of observing a sample proportion of at least 0.04 less than 0.84 is 0.273. B If the population proportion is 0.80, the probability of observing a sample proportion within 0.04 of 0.80 is 0.273. C If the population proportion is 0.80, the probability of observing a sample proportion at least 0.04 greater than 0.80 is 0.273. D If the…
The test statistic, t, is - 22.67. (Round to two decimal places as needed.) The P-value is 0.000. (Round to three decimal places as needed.) State the conclusion for the test. A. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. C. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
Q10. Suppose the alternative hypothesis for a particular test is given by H1: p ≠ 0.50. What is theP-value for this test if test statistic z = 1.35.a. 0.2010b. 0.0885c. 0.9115d. 0.1770
Perform the following hypothesis test: HO: µ = 10 H1: µ 10 The sample mean is 9.55, population standard deviation of 1.5 and a sample size of 51. Use a 5% significance level. What is the value of the test statistic? (Give your answer rounded to 2 decimals) (Be careful to make sure your + or - sign is correct)
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H 1: p≠0.377, the test statistic is z=3.06.
Select the most appropriate response. It is claimed that the mean age of bus drivers in Chicago is 59.3 years. If a hypothesis test is performed, how should you interpret a decision that fails to reject the null hypothesis? Question 2 options: There is not sufficient evidence to reject the claim µ = 59.3. There is sufficient evidence to reject the claim p = 59.3. There is not sufficient evidence to support the claim p = 59.3. There is sufficient evidence to support the claim u = 59.3.
Q1: A researcher was interested in the effect of exercise on stress levels. For the general population, the distribution of the Stress Battery Scale scores is normal with the mean of µ = 25 and the standard deviation of σ = 5. A sample of n = 100 participants was asked to exercise for three weeks and then reported their stress levels. The sample mean was ?X = 23. Conduct a hypothesis test and determine the effect of exercise. Use the two-tailed test α = .01 1.Type the null and research hypotheses in complete sentences. 2.Cut off points 3.Standard error and z-score -show your computation process 4.Your conclusion thoroughly.
Find the value of the standard score, z, and determine whether to reject the null hypothesis at a 0.01 significance level. Is the alternative hypothesis supported? Ho: μ = 19.1 meters, H₂: μ# 19.1 meters, n=144, x= 18.4 meters, o = 1.4 meters The value of the standard score is (Round to two decimal places as needed.) The critical value(s) is/are (Use a comma to separate answers as needed. Round to two decimal places as needed.) Determine whether the alternative hypothesis is supported at a 0.01 significance level. O A. The standard score is at least as extreme as the critical value(s). Reject Ho. The alternative hypothesis is supported. OB. The standard score is at least as extreme as the critical value(s). Do not reject Ho. The alternative hypothesis is not supported. C. The standard score is less extreme than the critical value(s). Reject Ho. The alternative hypothesis is supported. D. The standard score is less extreme than the critical value(s). Do not reject Ho. The alternative…
Only about 15% of all people can wiggle their ears. Is this percent different for millionaires? Of the 398 millionaires surveyed, 40 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = (please enter a decimal) H1:H1: ? μ p Select an answer < = ≠ > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different from 15% at αα = 0.05, so there is statistically insignificant evidence to conclude that the…
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You're fired! ~ Suppose that in a random sample of 252 employed Americans, there are 38 individuals who say that they would fire their boss if they could. Round all calculated values in this problem to 4 decimal places. 1. The value 38/252 = 0.1508 is a Statistic We want to use the information from the sample to conduct a hypothesis test to determine if fewer than 19% of employed Americans would fire their boss if they could. 2. Choose the null and alternative hypotheses for this test. Use appropriate notation. ОА. Но : р %3D 0.19, На : р 0.19 A 3. If you assume that the observations in the sample are independent, what is the smallest value the sample size could be to meet the conditions for this hypothesis test? А. 38 В. 10 С. 20 D. 67 ОЕ. 53 OF. None of the above
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