The figure to the right shows the results of a survey in which 1500 college graduates from the year 2016 were asked questions about employment.EmploymentCollege students' responses toquestions about employmentConstruct 99% confidence intervals for the population proportion of college students who gave each response.Expect to stay at firat employer for 3 or more yeers73%Completed an spprenticeship or intemship67%Employed in field of study61%Foel underemployed53%Prefer to work for a large company17%The 99% confidence interval for the proportion of college students that expect to stay at their first émployer for 3 or more years is (0.700, 0.760 ).(Round to three decimal places as needed.)The 99% confidence interval for the proportion of college students that have completed an apprenticeship or internship is (0.639. 0.701).(Round to three decimal places as needed.)The 99% confidence interval for the proportion of college students that are employed in their field of study is (0.578, 0.642).(Round to three decimal places as needed.)The 99% confidence interval for the proportion of college students that feel underemployed is (H D.(Round to three decimal places as needed.)

Given the, survey of 1500 college graduates. Where 53% graduates feel unemployed. We need to 99%…

Answered: The figure to the right shows the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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you want to find out the percent of people who use an iPhone so you survey 120 random adults of whom 57 use an iPhone. what is the 95% confidence interval for P the put portion of all adults who use iPhone
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The question was asking for 99% confidence interval for pop
Question
Several years ago, 44% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,075 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,075 surveyed, 479 indicated that they were satisfied. Construct a 95% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed. What are the null and alternative hypotheses? Ho: p = 0.44 versus H,: p 0.44 (Round to two decimal places as needed.) Use technology to find the 95% confidence interval. The lower is The upper bound is (Round to two decimal places as needed.)
Several years ago, 45% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,025 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,025 surveyed, 484 indicated that they were satisfied. Construct a 99% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed.
You want to estimate the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work. You took an SRS of 7 businesses and collected the following data for number of complaints in a year: men 1 3 2 4 6 3 5 women 8 7 6 3 5 12 15 Create a 90% confidence interval for the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work (in a year). You must do this using table C. If this is a 2 sample interval, be sure to specify who is population 1 and who is population 2. If this is a matched pairs interval, be sure to state the order you subtracted your data. Once you create your interval, give a sentence explaining the meaning of the interval (what the numbers in the interval mean, NOT the meaning of 95%) in context of this problem. Round to any appropriate number of decimals.
The figure to the right shows the results of a survey in which 2000 college graduates from the year 2016 were asked questions about employment. Construct 99% confidence intervals for the population proportion of college students who gave each response. Employment College students' responses to questions about employment Expect to stay at first employer for 3 or more years Completed an apprenticeship or intemship 70% 66% Employed in field of study 61% Feel underemployed 46% Prefer to work for a large company 15% The 99% confidence interval for the proportion of college students that expect to stay at their first employer for 3 or more years is (Round to three decimal places as needed.)
a critic points out that this 95 % confidence interval is only accurate if the statistic follows a normal distrubution , or if the normal model is a good approximation. is this true for this data? explain
The figure to the right shows the results of a survey in which 2000 college graduates from the year 2016 were asked questions about employment. Construct 99% confidence intervals for the population proportion of college students who gave each response. Employment College students' responses to questions about employment Expect to stay at first employer for 3 or more years Completed an apprenticeship or internship 70% 66% Employed in field of study 61% Feel underemployed 46% Prefer to work for a large company 15% The 9970 Conuenit initivaliui int proportion un cuiityt diuutid inal txptul iu diay al ineli idi empivyti iui j'ui muit years is (0.01, 0.121). (Round to three decimal places as needed.) The 99% confidence interval for the proportion of college students that have completed an apprenticeship or internship is (J.). (Round to three decimal places as needed.)
A poll showed that 40 out of 200 randomly chosen graduates of California medical schools last year intended to specialize in family practice. What is the width of a 95 percent confidence interval for the proportion that plan to specialize in family practice?
I chose Option 1 for this week’s discussion post. I want to estimate the population mean number of times adults between the ages of 30 and 45 went to the grocery store in the last week. I spoke with 12 adults and asked them how many times they went to the grocery store in the last week. The results were 0, 2, 2, 7, 5, 1, 0, 3, 1, 1, 4, and 3. Now calculate a 95% confidence interval for the population mean. (Round to three decimal places)

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