The figure shows wire section 1 of diameter D₁ = 5.00R and wire section 2 of diameter D2 = 4.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 2.30 m shown in section 2 is 11.0 μV. The number of charge carriers per unit volume is 8.30 × 1028 m³. What is the drift speed of the conduction electrons in section 1? Number i Units D₁ (1) (2)
The figure shows wire section 1 of diameter D₁ = 5.00R and wire section 2 of diameter D2 = 4.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 2.30 m shown in section 2 is 11.0 μV. The number of charge carriers per unit volume is 8.30 × 1028 m³. What is the drift speed of the conduction electrons in section 1? Number i Units D₁ (1) (2)
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Transcribed Image Text:The figure shows wire section 1 of diameter D₁ = 5.00R and wire section 2 of diameter D₂ = 4.00R, connected by a tapered section. The
wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the
wire's width. The electric potential change V along the length L = 2.30 m shown in section 2 is 11.0 μV. The number of charge carriers
per unit volume is 8.30 × 1028 m³. What is the drift speed of the conduction electrons in section 1?
Number
Units
D₁
(1)
(2)
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