The figure shows two circles with centers Q and S. Both the circles share a common tangent at point R, and T is tangent to both circles at J and K, and LN is tangent to both circles at N and M. R If PR = RS = 12, what is KL? %3D A. 6 В. 9 C. V288 D. V360

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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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Question 31

**Mathematics Problem:**

**Problem Statement:**

31. The figure shows two circles with centers \( Q \) and \( S \). Both circles share a common tangent at point \( R \), and \( \overrightarrow{LJ} \) is tangent to both circles at \( J \) and \( K \), and \( \overline{LN} \) is tangent to both circles at \( N \) and \( M \).

[Insert diagram of two circles with various labeled points here]

- The smaller circle has center \( Q \) and is tangent to the larger circle at point \( R \).
- The line segment \( \overline{PR} = \overline{RS} = 12 \).
- \( \overline{LJ} \) is a common tangent touching the smaller circle at \( J \) and the larger circle at \( K \).
- \( \overlap{LN} \) is another common tangent touching the smaller circle at \( M \) and the larger circle at \( N \).
- From point \( L \), the tangents \( LJ \) and \( LN \) extend outwards.

**Question:**
If \( PR = RS = 12 \), what is the length of \( KL \)?

**Choices:**
A. 6  
B. 9  
C. \( \sqrt{288} \)  
D. \( \sqrt{360} \)  

**Explanation of Diagram:**

In the diagram:
- Two circles are depicted, one smaller with center \( Q \) and one larger with center \( S \).
- Both circles touch at point \( R \).
- Two common external tangents are drawn: one through points \( J \) and \( K \) (denoted as \( \overline{LJ} \)), and another through points \( N \) and \( M \) (denoted as \( \overline{LN} \)).
- The common tangents (\( \overline{LJ} \) and \( \overline{LN} \)) intersect at a point labeled \( L \).
- The lengths \( PR \) and \( RS \) are given as 12.

**Solution:**

To solve for \( KL \), consider the geometric properties and distances involved due to the tangency conditions and the given lengths.

**Answer:** C. \( \sqrt{288} \)
Transcribed Image Text:**Mathematics Problem:** **Problem Statement:** 31. The figure shows two circles with centers \( Q \) and \( S \). Both circles share a common tangent at point \( R \), and \( \overrightarrow{LJ} \) is tangent to both circles at \( J \) and \( K \), and \( \overline{LN} \) is tangent to both circles at \( N \) and \( M \). [Insert diagram of two circles with various labeled points here] - The smaller circle has center \( Q \) and is tangent to the larger circle at point \( R \). - The line segment \( \overline{PR} = \overline{RS} = 12 \). - \( \overline{LJ} \) is a common tangent touching the smaller circle at \( J \) and the larger circle at \( K \). - \( \overlap{LN} \) is another common tangent touching the smaller circle at \( M \) and the larger circle at \( N \). - From point \( L \), the tangents \( LJ \) and \( LN \) extend outwards. **Question:** If \( PR = RS = 12 \), what is the length of \( KL \)? **Choices:** A. 6 B. 9 C. \( \sqrt{288} \) D. \( \sqrt{360} \) **Explanation of Diagram:** In the diagram: - Two circles are depicted, one smaller with center \( Q \) and one larger with center \( S \). - Both circles touch at point \( R \). - Two common external tangents are drawn: one through points \( J \) and \( K \) (denoted as \( \overline{LJ} \)), and another through points \( N \) and \( M \) (denoted as \( \overline{LN} \)). - The common tangents (\( \overline{LJ} \) and \( \overline{LN} \)) intersect at a point labeled \( L \). - The lengths \( PR \) and \( RS \) are given as 12. **Solution:** To solve for \( KL \), consider the geometric properties and distances involved due to the tangency conditions and the given lengths. **Answer:** C. \( \sqrt{288} \)
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