The figure shows three vectors. Vector A has a length of 32.0, vector B has a length of 66.0, and vector C has a length of 22.0. Solve the given equations. A. B = B. (A + C) = At what angles above and below the horizontal line k could vector A be at so that A B = 0? . 110° above or 70° below 20° above or 160° below 90° above or 70° below 90° above or 90° below C 70° 70° A 20° 160 B

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Chapter1: Units, Trigonometry. And Vectors
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The figure shows three vectors. Vector A has a length of 32.0,
vector B has a length of 66.0, and vector C has a length of
22.0.
Solve the given equations.
A.B=
B. (A + C) =
At what angles above and below the horizontal line
k
could vector A be at so that A B0?
.
110° above or 70° below
20° above or 160° below
90° above or 70° below
90° above or 90° below
C
70°
70°
A
20°
150
B
Transcribed Image Text:The figure shows three vectors. Vector A has a length of 32.0, vector B has a length of 66.0, and vector C has a length of 22.0. Solve the given equations. A.B= B. (A + C) = At what angles above and below the horizontal line k could vector A be at so that A B0? . 110° above or 70° below 20° above or 160° below 90° above or 70° below 90° above or 90° below C 70° 70° A 20° 150 B
Expert Solution
Step 1: Determine the given variable-

Vactor A length = 32.0 

Vector B length = 66.0 

Vector C length = 22.0 

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