The figure shows a small wad of putty colliding into a bar. The bar is initially hanging at rest from a pivot located at one end of the bar. The collision is completely inelastic. The bar has mass M = 3.67 kilograms and length L = 1.01 meters. The putty wad has mass m = 129 grams and is moving horizontally with vi = 1.12 m/s just before colliding with and sticking to the bar. The putty wad collides with the bar at d = 0.81 meters from the pivot. Note that the size of the putty wad is negligible compared to the length of the bar. 1.Calculate the angul
The figure shows a small wad of putty colliding into a bar. The bar is initially hanging at rest from a pivot located at one end of the bar. The collision is completely inelastic. The bar has mass M = 3.67 kilograms and length L = 1.01 meters. The putty wad has mass m = 129 grams and is moving horizontally with vi = 1.12 m/s just before colliding with and sticking to the bar. The putty wad collides with the bar at d = 0.81 meters from the pivot. Note that the size of the putty wad is negligible compared to the length of the bar. 1.Calculate the angul
The figure shows a small wad of putty colliding into a bar. The bar is initially hanging at rest from a pivot located at one end of the bar. The collision is completely inelastic. The bar has mass M = 3.67 kilograms and length L = 1.01 meters. The putty wad has mass m = 129 grams and is moving horizontally with vi = 1.12 m/s just before colliding with and sticking to the bar. The putty wad collides with the bar at d = 0.81 meters from the pivot. Note that the size of the putty wad is negligible compared to the length of the bar. 1.Calculate the angul
The figure shows a small wad of putty colliding into a bar. The bar is initially hanging at rest from a pivot located at one end of the bar. The collision is completely inelastic. The bar has mass M = 3.67 kilograms and length L = 1.01 meters. The putty wad has mass m = 129 grams and is moving horizontally with vi = 1.12 m/s just before colliding with and sticking to the bar. The putty wad collides with the bar at d = 0.81 meters from the pivot. Note that the size of the putty wad is negligible compared to the length of the bar.
1.Calculate the angular velocity (rad/s) of the bar just after the collision.
Transcribed Image Text:The image depicts a physics scenario involving rotational motion. Here's a detailed description for educational purposes:
The diagram shows a thin, vertical rod of mass "M" and length "L" that is free to rotate around a pivot point at the top. The rod is hinged at the pivot, allowing it to swing like a pendulum.
A point mass "m" is moving horizontally towards the rod with an initial velocity "v_i". The distance "d" is marked on the rod, measuring from the pivot to a specific point where the mass might strike the rod.
**Key Elements:**
- **Rod (Vertical Line):** Represents a thin, rigid rod of mass "M" and length "L".
- **Pivot (Circular Mark):** The fixed point at the top of the rod around which the rod can rotate.
- **Mass "m" (Small Circle):** A separate object approaching the rod with velocity "v_i".
- **Initial Velocity "v_i" (Arrow):** Indicates the direction and speed of mass "m" as it approaches the rod.
- **Distances "d" and "L":**
- "d": The point on the rod where the mass might impact, starting from the pivot.
- "L": The total length of the rod from the pivot to the bottom.
This diagram can be used to illustrate concepts such as the conservation of angular momentum, torque, and rotational dynamics in a physics course.
Definition Definition Rate of change of angular displacement. Angular velocity indicates how fast an object is rotating. It is a vector quantity and has both magnitude and direction. The magnitude of angular velocity is represented by the length of the vector and the direction of angular velocity is represented by the right-hand thumb rule. It is generally represented by ω.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
