The figure shows a capacitor network with Vab = 17 V, C₁ = 10 nF, C₂ = 6 nF, and C3 = 11 nF. Find the charge on capacitor 2 (in nC). C₁ C₂ C3

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### Capacitor Network Analysis

**Problem Statement:**

The figure shows a capacitor network with a total voltage across points \( V_{ab} = 17 \, \text{V} \). The capacitance values are as follows:
- \( C_1 = 10 \, \text{nF} \)
- \( C_2 = 6 \, \text{nF} \)
- \( C_3 = 11 \, \text{nF} \)

The task is to find the charge on capacitor 2 (\( C_2 \)) in nanocoulombs (nC).

**Diagram Explanation:**

The diagram illustrates three capacitors connected in series between two points, \( a \) and \( b \). Each capacitor is represented with parallel lines indicating the capacitor plates. The capacitors are labeled sequentially as \( C_1, C_2, \) and \( C_3 \).

**Solution:**

For capacitors in series, the charge \( Q \) on each capacitor is equal. Using the formula for capacitors in series and the given total voltage, the charge on \( C_2 \) can be calculated.

**Correct Answer:**

The charge on capacitor 2, \( C_2 \), is 47.5424 nC, with a margin of error of ±1%.
Transcribed Image Text:### Capacitor Network Analysis **Problem Statement:** The figure shows a capacitor network with a total voltage across points \( V_{ab} = 17 \, \text{V} \). The capacitance values are as follows: - \( C_1 = 10 \, \text{nF} \) - \( C_2 = 6 \, \text{nF} \) - \( C_3 = 11 \, \text{nF} \) The task is to find the charge on capacitor 2 (\( C_2 \)) in nanocoulombs (nC). **Diagram Explanation:** The diagram illustrates three capacitors connected in series between two points, \( a \) and \( b \). Each capacitor is represented with parallel lines indicating the capacitor plates. The capacitors are labeled sequentially as \( C_1, C_2, \) and \( C_3 \). **Solution:** For capacitors in series, the charge \( Q \) on each capacitor is equal. Using the formula for capacitors in series and the given total voltage, the charge on \( C_2 \) can be calculated. **Correct Answer:** The charge on capacitor 2, \( C_2 \), is 47.5424 nC, with a margin of error of ±1%.
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