The figure illustrates three edge views of a square loop with sides of length $ \ell = 0.220 \, \text{m} $, placed in a magnetic field of magnitude $ 2.25 \, \text{T} $. The task is to calculate the magnetic flux ($ \Phi $, in Weber or Wb) through the loop when it is oriented in three different ways: perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field.**Diagrams:**1. **First diagram (left):** - The square loop is perpendicular to the magnetic field ($ \vec{B} $). - The magnetic field lines, represented by green arrows, pass directly through the loop. - Calculation shows the magnetic flux as $ \Phi = 0.1089 \, \text{Wb} $.2. **Second diagram (middle):** - The loop is tilted at an angle of 60.0° to the magnetic field. - The magnetic field lines still intersect the loop but at an angle. - The calculation gives the magnetic flux as $ \Phi = 0.0640 \, \text{Wb} $, indicating reduced flux compared to the perpendicular orientation.3. **Third diagram (right):** - The loop is parallel to the magnetic field. - No magnetic field lines pass through the loop. - Calculation implies no magnetic flux through the loop in this orientation.**Hint:**- For (a), when the loop is perpendicular to the magnetic field, the flux calculation is correct: $ 0.1089 \, \text{Wb} $.- For (b), when the loop is at 60.0° from the magnetic field, the flux calculation is incorrect: $ 0.0640 \, \text{Wb} $ (marked with a red cross).This understanding highlights the principle that magnetic flux depends on the orientation of the loop relative to the magnetic field.

Given data: A square loop Side length (l) = 0.220 m Magnetic field (B) = 2.25 T Required: The the…

The figure below shows three edge views of a square loop with sides of length = 0.220 m in a magnetic field of magnitude 2.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field. HINT (a) perpendicular to the magnetic field Wb 0.1089 B (b) 60.0° from the magnetic field 0.0640 XWb y B 60.0° B

The figure below shows three edge views of a square loop with sides of length = 0.220 m in a magnetic field of magnitude 2.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field. HINT (a) perpendicular to the magnetic field Wb 0.1089 B (b) 60.0° from the magnetic field 0.0640 XWb y B 60.0° B

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

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The figure illustrates three edge views of a square loop with sides of length $ \ell = 0.220 \, \text{m} $, placed in a magnetic field of magnitude $ 2.25 \, \text{T} $. The task is to calculate the magnetic flux ($ \Phi $, in Weber or Wb) through the loop when it is oriented in three different ways: perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field.

**Diagrams:**

1. **First diagram (left):**
- The square loop is perpendicular to the magnetic field ($ \vec{B} $).
- The magnetic field lines, represented by green arrows, pass directly through the loop.
- Calculation shows the magnetic flux as $ \Phi = 0.1089 \, \text{Wb} $.

2. **Second diagram (middle):**
- The loop is tilted at an angle of 60.0° to the magnetic field.
- The magnetic field lines still intersect the loop but at an angle.
- The calculation gives the magnetic flux as $ \Phi = 0.0640 \, \text{Wb} $, indicating reduced flux compared to the perpendicular orientation.

3. **Third diagram (right):**
- The loop is parallel to the magnetic field.
- No magnetic field lines pass through the loop.
- Calculation implies no magnetic flux through the loop in this orientation.

**Hint:**
- For (a), when the loop is perpendicular to the magnetic field, the flux calculation is correct: $ 0.1089 \, \text{Wb} $.
- For (b), when the loop is at 60.0° from the magnetic field, the flux calculation is incorrect: $ 0.0640 \, \text{Wb} $ (marked with a red cross).

This understanding highlights the principle that magnetic flux depends on the orientation of the loop relative to the magnetic field.

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