The figure below shows the allocation for file jeep.directoryfilestartend25jeep12013014015016 117018019020021O22023024O25126O27028O29O300310LinkedLinearO IndexedO Contiguous

File allocation technique decides how file will be stored in memory. There are 3 types of file…

The figure below shows the allocation for file jeep. directory file jeep end 25 start 40 50 60 7O 120130140150 16 1170180190 20021O22023O 24O251260270 28O29O30O310 O Linked O Linear O Indexed O Contiguous

The figure below shows the allocation for file jeep. directory file jeep end 25 start 40 50 60 7O 120130140150 16 1170180190 20021O22023O 24O251260270 28O29O30O310 O Linked O Linear O Indexed O Contiguous

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Build an application for a car rental company. It should offer the following features:• Maintain a customer database in a file:o Register / add new customers. Customer information should include▪ Customer ID number▪ Name▪ Phone numbero Search customer database by:▪ Customer ID number▪ Name▪ Phone numberAnd print out the matching records NOTE ; i need the answer to be by switch
Focus on string operations and methods You work for a small company that keeps the following information about its clients: • first name • last name • a 5-digit user code assigned by your company. The information is stored in a file clients.txt with the information for each client on one line (last name first), with commas between the parts. For example Jones, Sally,00345 Lin ,Nenya,00548 Fule,A,00000 Smythe , Mary Ann , 00012 Your job is to create a program assign usernames for a login system. First: write a function named get_parts(string) that will that will receive as its arguments a string with the client data for one client, for example “Lin ,Nenya,00548”, and return the separate first name, last name, and client code. You should remove any extra whitespace from the beginning and newlines from the end of the parts. You’ll need to use some of the string methods that we covered in this lesson You can test your function by with a main() that is just the function call with the…
SAME PARAMETERS: In the RENTALS table shown in fig 2, 40 customers have created 50 rental contracts over time. A RENTALS record is 122 bytes and the block size for your OS is set to 1024 bytes with each block having a 1 byte pointer to the next written block as well as a 1 byte pointer to the next physically consecutive block. Assuming spanned organization, how many blocks do you estimate the RENTALS file is using at its current size? multiple choice a.50 b.6 c.400 d.7
JAVA
Tracing Exercise: What will be displayed exactly after the following .m file is executed? n = [1 -88 300 27 -10 17]; p = n(1); for j = 3:length(n), p = p + n(j) end k = 0; tt = 10; while k < 15 k = k + 3 tt = tt + k end disp (k) disp (tt)
write a batch file which it can Sort based on the column in file. Important that the user can choose which column . Look what is batch file : https://en.wikipedia.org/wiki/Batch_file The textfile : ID Name Weight Long Class Age012 Eric 56 156 7 13045 Richard 78 178 9 17098 Maya 60 164 10 16072 Anna 56 152 8 14034 Helena 76 169 11 18022 Kevin 66 162 6 12093 Peter 99 170 12 19
JAVA: Use the "natural split" algorithm on the file split.txt and answer the following question: How many elements are in the first list? Split.txt file 200494 774 644 345 521 61 27 28 584 569 66 857 210 2 211 675 548 596 188 647 671 517 408 475 615 113 731 522 850 17 640 940 556 517 602 935 76 578 880 428 168 394 381 497 247 368 137 138 619 973 895 106 838 45 921 800 681 660 490 427 937 917 786 959 152 604 837 749 684 963 926 963 988 492 385 458 788 7 62 46 932 996 787 634 34 616 71 128 686 578 923 532 933 545 100 224 895 595 342 933 934 797 120 565 495 884 237 648 843 599 157 843 192 279 301 649 382 881 667 178 126 746 44 601 22 52 769 708 991 83 447 786 525 168 328 922 153 367 22 689 834 774 93 110 547 597 644 726 237 20 370 573 391 225 750 897 956 839 951 455 8 509 746 338 576 276 277 341 274 891 723 53 966 271 50 990 493 823 833 306 619 461 768 832 736 759 920 451 549 833 911 123 907 225 252 179 177 272 747 859
Select a states that is not q2 from the GNFA to delete. Then, create a new GNFA for the deleted state that is equivalent to M but does not have the selected state.
Variable Length Record Load the pipe-delimited file P. It is organized with 3 fields on each line: firstname|lastnameļbirthday. Search for the firstname F and lastname L, replacing the birthday with B. Write the file back out in the same pipe-delimited format. Check It! Program Output Your program output did not match the expected output. Your output: Adam|Smith|11111985 Theodore|Anderson|20031990 Adam KISmith|09091999 Monty|Biscuit-Barrel|18101980 00000000 Ruthy|Anderson|06062010 Expected output: Adam|Smith|11111985 Theodore|Anderson|20031990 Adam K|Smith|09091999 Monty|Biscuit-Barrel|18101980 Adam|Smithers|00000000 Ruthy|Anderson|06062010
Do it in intelij IDE otherwise I will give down vote Write a python program in intelij IDE to convert a dictionary into json format and check whether the created json file working or not
HAHAAAAAAHN HNM1000 OHNM 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 27 28 30 31 32 section . data .section .text .globl _start start: pushq $4 pushq $3 call function-A addq $16, $rsp movg %rax, %rbx movq $1, rax int $0x80 .type function-A, @function function-A: pushq rbp movq rsp, rbp. subq $8, rsp movg 16(%rbp), %rbx movq 24 (rbp), rcx movg %rbx, -8(%rbp) label-A: #variable y #variable z cmpq $1, $rcx je label-B movq -8 (&rbp), rax imulg %rbx, srax movq krax, -8 (%rbp) decq rcx jmp label-A label-B: movq -8 (Srbp), rax movq rbp, rsp popq &rbp ret
In a contiguous allocation, if the file has n blocks long and starts at location b, the starting and last blocks being occupied by the file is ___ respectively. a. b and b + n - 1 b. n and b + n + 2 c. b and b + n d. n and n + b -1