The figure below shows an initially stationary block of mass m on a floor. A force of magnitude F = 0.490mg is then applied at upward angle 0 = 23°. (a) What is the magnitude of the acceleration of the block across the floor if the friction coefficients are ls = 0.595 and uy = 0.490? m/s2 (b) What is the magnitude of the acceleration of the block across the floor if the friction coefficients are µs = 0.395 and ly = 0.305? m/s²
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
Acceleration Due to Gravity
In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
![**Problem Description:**
The figure below shows an initially stationary block of mass \( m \) on a floor. A force of magnitude \( F = 0.490mg \) is then applied at an upward angle \( \theta = 23^\circ \).
**Diagram Explanation:**
- The diagram features a block on a flat surface with an applied force \( \vec{F} \) at an angle \( \theta = 23^\circ \) from the horizontal. The positive direction of the \( y \)-axis is upwards, and the positive direction of the \( x \)-axis is to the right.
**Questions:**
(a) What is the magnitude of the acceleration of the block across the floor if the friction coefficients are \( \mu_s = 0.595 \) and \( \mu_k = 0.490 \)?
- Answer Box: [ ] m/s\(^2\)
(b) What is the magnitude of the acceleration of the block across the floor if the friction coefficients are \( \mu_s = 0.395 \) and \( \mu_k = 0.305 \)?
- Answer Box: [ ] m/s\(^2\)
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