The figure below shows a snapshot graph at t = 0s of a wave pulse on a string. The pulse is traveling to the right at 100 cm/s. Draw snapshot graphs of the wave pulse at t = -0.01 s and t = 0.01s 2 Atr=0 s 100 cm/s 4 6 x (cm)

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### Understanding Wave Pulse Propagation

The figure below illustrates a snapshot graph of a wave pulse on a string at time \( t = 0 \) seconds. The pulse is moving to the right with a velocity of 100 cm/s. To understand the wave dynamics, we are asked to sketch the snapshot graphs of the wave pulse at \( t = -0.01 \) seconds and \( t = 0.01 \) seconds.

#### Snapshot Graph at \( t = 0 \) seconds

![Wave Pulse at t=0 s](image-link)

The wave profile at \( t = 0 \) seconds displays the initial shape of the wave pulse. 

##### Description of the Graph:
- **Axes**: The horizontal axis represents the position \( x \) in centimeters (cm), and the vertical axis represents the displacement \( y \).
- **Wave Shape**:
  - The wave begins at \( x = 0 \) cm.
  - The positive peak reaches approximately at \( x = 2 \) cm.
  - The wave crosses the x-axis at \( x = 4 \) cm.
  - A negative trough is found between \( x = 4 \) cm and \( x = 6 \) cm.

#### Explanation of Wave Propagation:
Due to the pulse traveling to the right at 100 cm/s, we can calculate the displacement for other times using the equation:
\[ \Delta x = v \cdot \Delta t \]
Where:
- \( \Delta x \) is the spatial displacement,
- \( v \) is the velocity (100 cm/s),
- \( \Delta t \) is the time change.

##### For \( t = -0.01 \) seconds:
\[ \Delta x = 100 \, \text{cm/s} \cdot (-0.01 \, \text{s}) = -1 \, \text{cm} \]
- The wave pulse shifts to the left by 1 cm compared to its position at \( t = 0 \) seconds.

##### For \( t = 0.01 \) seconds:
\[ \Delta x = 100 \, \text{cm/s} \cdot 0.01 \, \text{s} = 1 \, \text{cm} \]
- The wave pulse shifts to the right by 1 cm compared to its position at \( t = 0 \) seconds.

####
Transcribed Image Text:### Understanding Wave Pulse Propagation The figure below illustrates a snapshot graph of a wave pulse on a string at time \( t = 0 \) seconds. The pulse is moving to the right with a velocity of 100 cm/s. To understand the wave dynamics, we are asked to sketch the snapshot graphs of the wave pulse at \( t = -0.01 \) seconds and \( t = 0.01 \) seconds. #### Snapshot Graph at \( t = 0 \) seconds ![Wave Pulse at t=0 s](image-link) The wave profile at \( t = 0 \) seconds displays the initial shape of the wave pulse. ##### Description of the Graph: - **Axes**: The horizontal axis represents the position \( x \) in centimeters (cm), and the vertical axis represents the displacement \( y \). - **Wave Shape**: - The wave begins at \( x = 0 \) cm. - The positive peak reaches approximately at \( x = 2 \) cm. - The wave crosses the x-axis at \( x = 4 \) cm. - A negative trough is found between \( x = 4 \) cm and \( x = 6 \) cm. #### Explanation of Wave Propagation: Due to the pulse traveling to the right at 100 cm/s, we can calculate the displacement for other times using the equation: \[ \Delta x = v \cdot \Delta t \] Where: - \( \Delta x \) is the spatial displacement, - \( v \) is the velocity (100 cm/s), - \( \Delta t \) is the time change. ##### For \( t = -0.01 \) seconds: \[ \Delta x = 100 \, \text{cm/s} \cdot (-0.01 \, \text{s}) = -1 \, \text{cm} \] - The wave pulse shifts to the left by 1 cm compared to its position at \( t = 0 \) seconds. ##### For \( t = 0.01 \) seconds: \[ \Delta x = 100 \, \text{cm/s} \cdot 0.01 \, \text{s} = 1 \, \text{cm} \] - The wave pulse shifts to the right by 1 cm compared to its position at \( t = 0 \) seconds. ####
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