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The figure below shows a rectangular tank of dimensions ho = 2.5 m and b = 2 m is filled to the brim with a liquid of specific gravity 1.1 (tank is 1 m into plane of figure). The tank is subjected to a horizontal acceleration ax, and 30% of the liquid spills over. Determine the difference in liquid pressures at the lower left-hand corner (Point E) and lower right-hand corner of the tank (Point F). PE-PF= 1. [15.70090597, 16.672095597 kPa.

The figure below shows a rectangular tank of dimensions ho = 2.5 m and b = 2 m is filled to the brim with a liquid of specific gravity 1.1 (tank is 1 m into plane of figure). The tank is subjected to a horizontal acceleration ax, and 30% of the liquid spills over. Determine the difference in liquid pressures at the lower left-hand corner (Point E) and lower right-hand corner of the tank (Point F). PE-PF= 1. [15.70090597, 16.672095597 kPa.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The figure below shows a rectangular tank of dimensions ho = 2.5 m and b = 2 m is filled to the brim with a liquid of specific gravity 1.1 (tank is 1 m into plane of figure). The tank is subjected to a horizontal acceleration ax, and 30% of the liquid spills over. Determine the difference in liquid pressures at the lower left-hand corner (Point E) and lower right-hand corner of the tank (Point F). PE-PF= 1. [15.70090597, 16.672095597 Free surface ho Liquid X b Liquid at rest ➡ho kPa. 9 Free surface Liquid b ax Under constant acceleration
Transcribed Image Text:The figure below shows a rectangular tank of dimensions ho = 2.5 m and b = 2 m is filled to the brim with a liquid of specific gravity 1.1 (tank is 1 m into plane of figure). The tank is subjected to a horizontal acceleration ax, and 30% of the liquid spills over. Determine the difference in liquid pressures at the lower left-hand corner (Point E) and lower right-hand corner of the tank (Point F). PE-PF= 1. [15.70090597, 16.672095597 Free surface ho Liquid X b Liquid at rest ➡ho kPa. 9 Free surface Liquid b ax Under constant acceleration
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